如何删除字符串中的特殊字符模式

Question

I have a string name s,

String s = "He can speak English and Sinhala.[1]He<ename> has edited 12 CSE Staff Research Publications.[1][2]"

I want to remove [1] and [1][2] from the string. Note that we can have any number within the square brackets and any no of square brackets(like [number][number][number]... ). I tried using this,

String removedNoTag = s.replaceAll("[\\[0-9\\]]","");

Yes it removes all [number].. patterns. But it also removes all numbers within the text (It removes 12 also).

Can anyone please tell me how to do this?

Answer 1

尝试以下操作： String removedNoTag = s.replaceAll("\\\\[\\\\d+\\\\]","");

Answer 2

You are escaping the wrong brackets in your regular expression. What you are looking for is:

String removedNoTag = s.replaceAll("\\[[0-9]+\\]","");

or

String removedNoTag = s.replaceAll("\\[\\d+\\]","");

With \\d being the "short form of [0-9] .

Answer 3

Your outer brackets define a set of characters to remove. That set is defined as [ , ] and 0-9 . So any combination of those is detected (for example [] , 2 , ] , [3] , [324] , ]1[[[ ).

Instead try \\\\[\\\\d+\\\\] , which means the open bracket, one or more digits ( \\d ) and a closing bracket.

Answer 4

Because it removes any instance of a character that is either a number or a bracket.

replace with : \\\\[[0-9]+\\\\]