[英]mySQL UPDATE all columns from corresponding columns in another table
I have two tables with identical schema. 我有两个具有相同架构的表。 And lots of columns! 还有很多专栏!
I can update a record from the corresponding table by doing 我可以通过执行来更新相应表中的记录
update t1
join t2 on t2.id=t1.id
set t1.column1=t2.column1,
t1.column2=t2.column2...
where t2.columnx > 123;
But I have a ton of fields and am by nature, a lazy bastard who'd rather shave a yak and post on SE than type out a list of columns (possibly missing 1). 但是我有很多田地,而且本质上是一个懒惰的混蛋,他宁愿刮牦牛并在SE上发帖,也不会列出一列列(可能缺少1)。
Other than some funky solution that writes out the column list to a text file etc, is there valid mySQL syntax that skips the explicit listing of all the columns and works more like INSERT...SELECT? 除了将列列表写入文本文件等的一些时髦的解决方案之外,是否有有效的mySQL语法跳过所有列的显式列表并且更像INSERT ... SELECT?
REPLACE INTO t1 SELECT * FROM t2 WHERE columnx>123;
Try to use REPLACE INTO ... SELECT ...
syntax http://dev.mysql.com/doc/refman/5.0/en/replace.html 尝试使用REPLACE INTO ... SELECT ...
语法http://dev.mysql.com/doc/refman/5.0/en/replace.html
REPLACE INTO t1 SELECT t2.* FROM t2, t1 WHERE t1.columnx>123 AND t1.id=t2.id;
Warning! 警告! Not tested! 没测试过!
This code would work only if tables have unique indexes on id
columns. 仅当表在id
列上具有唯一索引时,此代码才有效。
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