返回数组中的MySQL行

Question

I've been working on a OOP method that is supposed to return the rows of a MySQL query. I have to have the data array in the format:

$rows = array('row'=> rownum, 'fld1'=> fldval .... 'fldn' => fldval);

What I have encountered are the two problems of either:

returns

$rows = array('0'=>fldval, 'fld1'=> fldval .... 'n'=> fldval, 'fldn' => fldval);

or single row of

$rows = array('fld1'=> fldval .... 'fldn' => fldval);

Little frustrated as every PHP mysql function I have tried has some sort to goofy crap flaw and will not do a straight out process.

I assume there is a good example somewhere, that can get me past the crap limitations, but haven't found anything useful yet!

I've tried all of the following:

$row = mysql_result($db_res,$n);
$row = mysql_fetch_array($db_res);
$row = mysql_fetch_assoc($db_res);
$row = mysql_fetch_object($db_res);
$row = mysql_fetch_row($db_res);  

None have worked successfully! For getting out the bogus "numeric" array entries. I wrote:

foreach ($row as $k => $v)
   if (is_numeric($k)) { continue; }
   $result[$k] = $v;
}  // end foreach $row
$row = array_push($row, 'row'=>$rownum, $result);

Hoping someone has a link.

Answer 1

$list = array();
$query = "SELECT value FROM table";
$resource = mysql_query($query);
while($row = mysql_fetch_assoc($resource))
{
   $list['fld' . (1 + count($list))] = $row['value'];
}
$list = array('row' => count($list)) + $list;

if table have 3 row, the code above is going to give you a array like:

array(
    'row' => 3,
    'fld1' => 12,
    'fld2' => 34,
    'fld3' => 56
);