[英]C - display int as hex using bitwise operators
I was reading the SO question about displaying integers as hex using C (without using %x, by using a custom function) and the first answer mentions using bitwise operators to achieve the goal. 我正在阅读有关使用C将整数显示为十六进制的SO问题(不使用%x,而是通过使用自定义函数),第一个答案提到了使用按位运算符来实现目标。
But I can't figure it out on my own. 但是我无法自行解决。 Can anyone tell me how this would be done?
谁能告诉我该怎么做?
I hope this makes it a little clear to you. 希望这对您有所帮助。
char *intToHex(unsigned input)
{
char *output = malloc(sizeof(unsigned) * 2 + 3);
strcpy(output, "0x00000000");
static char HEX_ARRAY[] = "0123456789ABCDEF";
//Initialization of 'converted' object
// represents the end of the string.
int index = 9;
while (input > 0 )
{
output[index--] = HEX_ARRAY[(input & 0xF)];
//Prepend (HEX_ARRAY[n & 0xF]) char to converted;
input >>= 4;
}
return output;
}
This is not an "optimal solution". 这不是 “最佳解决方案”。 Other posters in the same thread suggested a table lookup, which is much, much better.
同一线程中的其他张贴者建议进行表查找,这要好得多。
But, to answer your question, this is pretty much what he was suggesting: 但是,要回答您的问题,这几乎是他的建议:
Convert integer to hex
将整数转换为十六进制
Each 4 bits of an integer maps to exactly one hex digit, if the value of those four bits is less than 10, then its ASCII representation is '0' + value, otherwise it is 'A' + value - 10.
整数的每个4位都精确映射到一个十六进制数字,如果这四个位的值小于10,则其ASCII表示形式为'0'+值,否则为'A'+值-10。
You can extract each group of four digits by shifting and masking.
您可以通过移位和屏蔽来提取每组四个数字。 The mask value is 0x0f, and assuming a 32bit integer, the right shift starts at 24 bits and decrements by four for each successive digit.
掩码值为0x0f,并假设为32位整数,则右移从24位开始,并对于每个连续的数字递减4。
#include <stdio.h>
unsigned int
hex_digit (int ival, int ishift)
{
ival = (ival >> ishift) & 0xf;
if (ival < 10)
ival += '0';
else
ival += ('a' + ival - 10);
return ival;
}
int
main()
{
int i = 100;
char s[9];
s[0] = hex_digit (i, 28);
s[1] = hex_digit (i, 24);
s[2] = hex_digit (i, 20);
s[3] = hex_digit (i, 16);
s[4] = hex_digit (i, 12);
s[5] = hex_digit (i, 8);
s[6] = hex_digit (i, 4);
s[7] = hex_digit (i, 0);
s[8] = '\0';
printf ("hex(%d)=%s\n", i, s);
return 0;
}
SAMPLE OUTPUT: 样品输出:
gcc -o tmp -g -Wall -pedantic tmp.c
./tmp
hex(100)=00000064
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