[英]how to send data to server from iphone application
I am sending data from iphone application to server using php but data is not inserted in the data base when i post the data in return it just sents the [] in echo. 我正在使用php将数据从iPhone应用程序发送到服务器,但是当我以返回形式发布数据时,数据没有插入数据库中,它只是在回显中发送了[]。
My iPhone Code 我的iPhone代码
-(void)submitSurveyAnswers{
NSString*survey_question_response_id="1";
NSString*survey_id=@"1";
NSString *question_id =@"1";
NSString *survey_response_answer_id =@"1";
NSString *post =[[NSString alloc] initWithFormat:@"survey_question_response_id=%@&survey_id=%@&question_id=%@&survey_response_answer_id=%@",survey_question_response_id,survey_id,question_id,survey_response_answer_id];
NSLog(post);
NSURL *url=[NSURL URLWithString:@"http://myserver-solutions.com/app/surveyAnswer.php?"];
NSData *postData = [post dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES];
NSString *postLength = [NSString stringWithFormat:@"%d", [postData length]];
NSMutableURLRequest *request = [[NSMutableURLRequest alloc] init] ;
[request setURL:url];
[request setHTTPMethod:@"POST"];
[request setValue:postLength forHTTPHeaderField:@"Content-Length"];
[request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"];
[request setHTTPBody:postData];
NSError *error;
NSURLResponse *response;
NSData *urlData=[NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&error];
NSString *data=[[NSString alloc]initWithData:urlData encoding:NSUTF8StringEncoding];
NSLog(@"%@",data);
}
Here is the my php code 这是我的PHP代码
<?php
$host = "";
$user = "";
$pass = "";
$database = "";
$linkID = mysql_connect($host, $user, $pass) or die("Could not connect to host.");
mysql_select_db($database, $linkID) or die("Could not find database.");
$survey_question_response_id=$_POST['survey_question_response_id'];
$survey_id=$_POST['survey_id'];
$question_id=$_POST['question_id'];
$survey_response_answer_id=$_POST['survey_response_answer_id'];
echo($survey_question_response_id);
$query=("INSERT INTO survey_question_responses
(survey_question_response_id,survey_id,question_id,survey_response_answer_id) (survey_question_response_id,survey_id,question_id,survey_response_answer_id)
VALUES ('$survey_question_response_id', '$survey_id','$question_id','$survey_response_answer_id')");
mysql_query($query,$con);
printf("Records inserted: %d\n", mysql_affected_rows());
echo($survey_id)
?>
I have a full example on Github to dynamically create forms and submit them to a POST server. 我在Github上一个完整的例子来动态地创建表单并提交到服务器POST。 You may be able to use it depending upon how complex your forms are.
您可能可以使用它,具体取决于表单的复杂程度。 Each form is described in a plist and is very dynamic.
每种形式都在plist中进行了描述,并且非常动态。
If it is missing support for any desired form type (checkboxes, drop-down, etc.), let me know and I'd be happy to add them. 如果缺少对任何所需表单类型(复选框,下拉列表等)的支持,请告诉我,我很乐意添加它们。 (I only needed text-based input in my forms so far, but if there is a demand, I'd like to expand it to more complex items too!)
(到目前为止,我只需要在表单中使用基于文本的输入,但是如果有需求,我也想将其扩展到更复杂的项目!)
(A PHP file is also included to catch the response.) (还包括一个PHP文件来捕获响应。)
https://github.com/mikecheckDev/MDContactForm https://github.com/mikecheckDev/MDContactForm
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