当将字符串和int指针一起用作函数参数时，C ++程序崩溃

Question

I have a super weird problem with glibc on Ubuntu.

Sample program test.cpp:

#include <iostream>
#include <stdio.h>
#include <stdlib.h>

using namespace std;

bool abc(string unitstr,int *data)
{        

}

int main(int argc,char *argv[])
{

  int *dd3 = new int(8); 
  dd3[0]=1;dd3[1]=2;dd3[2]=3;dd3[3]=4;
  dd3[4]=5;dd3[5]=6;dd3[6]=7;dd3[7]=8;
  abc("sss",dd3);

  return 1;
}

Compile and run:

g++ test.cpp
a.out

Result:

a.out: malloc.c:2451: sYSMALLOc: Assertion `(old_top == (((mbinptr) (((char *) &((av)->bins[((1) - 1) * 2])) - __builtin_offsetof (struct malloc_chunk, fd)))) && old_size == 0) || ((unsigned long) (old_size) >= (unsigned long)((((__builtin_offsetof (struct malloc_chunk, fd_nextsize))+((2 * (sizeof(size_t))) - 1)) & ~((2 * (sizeof(size_t))) - 1))) && ((old_top)->size & 0x1) && ((unsigned long)old_end & pagemask) == 0)' failed.
Abort (core dumped)

Answer 1

With this line:

int *dd3 = new int(8);

You're allocating and initializing a scalar , not an array: a single int , initialized with the value 8 .

You need:

int *dd3 = new int[8];

Answer 2

int *dd3 = new int(8);

This statement only allocates space for a single integer (and then initializes it with the number 8). You then proceed in using this pointer like a larger array, leading to undefined behavior that may (and indeed, seems to) manifest itself later on.

Using new here seems unnecessary (and exception-unsafe, if nothing else). Just use a vector and be done with it (should you want to be able to resize the block inside the function, just pass the vector instead of a pointer).

Answer 3

This line allocates a single int and initializes it to the value 8 :

int *dd3 = new int(8);

If you want an array of 8 ints do this instead:

int *dd3 = new int[8];

Don't forget to correctly return the memory when you are done:

delete [] dd3;