如何迭代连接子目录中的文件

Question

I have a bunch of directories, in each directory I have bunch of sub directories, in each sub directory I have 1 files named x1 and might have y1 z1 as well.

I want to have a shell script that for each directory, goes through sub directories and concatenate all the x1 s to one file and also all the y1 s and all the z1 s.

I have tried

cat ./*/*.x1 >test

I don't know how does it work with for each

Answer 1

If you're using zsh this for loop work:

for dir in *(/); do
  cat "$dir"/*.x1 > "$dir"/combined.x1
  [[ -n "$dir"/*.y1 ]] && cat "$dir"/*.y1 > "$dir"/combined.y1
  [[ -n "$dir"/*.z1 ]] && cat "$di"r/*.z1 > "$dir"/combined.z1
done

Update

For bash it seems you only need to update the dir pattern:

for dir in */; do
  cat "$dir"/*.x1 > "$dir"/combined.x1
  [[ -n "$dir"/*.y1 ]] && cat "$dir"/*.y1 > "$dir"/combined.y1
  [[ -n "$dir"/*.z1 ]] && cat "$di"r/*.z1 > "$dir"/combined.z1
done