[英]How to parse XML from assets?
Suppose I have an XML file in my assets with such data 假设我的资产中有一个包含此类数据的XML文件
<mods day="30" month="8" year="2012">
<mod id="1" name="1a">Hello123</mod>
<mod id="2" name="2a">Hello123</mod>
<mod id="3" name="3a">Hello123</mod>
</mods>
<mods day="31" month="8" year="2012">
<mod id="1" name="1a">Hello123</mod>
<mod id="2" name="2a">Hello123</mod>
<mod id="3" name="3a">Hello123</mod>
</mods>
and I need to find a certain "mod" parameter by inputting day, month, year and id. 并且我需要通过输入日期,月份,年份和ID查找特定的“ mod”参数。
here's how far I got. 这是我走了多远。
c.setTime(new Date());
String y = sdy.format(c.getTime());
String m = sdm.format(c.getTime());
String d = sdd.format(c.getTime());
InputStream istr = this.getAssets().open("mods.xml");
XmlPullParserFactory factory = XmlPullParserFactory.newInstance();
factory.setNamespaceAware(true);
XmlPullParser xrp;
xrp = factory.newPullParser();
xrp.setInput(istr, "UTF-8");
// not sure what to do next...
If I got it right, now I need to somehow query this xrp with my needed parameters, right? 如果我做对了,现在我需要以某种方式用所需的参数查询此xrp,对吗?
Thanks! 谢谢!
Putting the XML as an XML resource in res/xml/
, not in assets/
, it will parse 10x faster, courtesy of the optimizations in place for XML resources. 将XML作为XML资源放置在
res/xml/
,而不是在assets/
,由于对XML资源进行了优化,因此解析速度将提高10倍。 Hence, I recommend using XML resources instead of XML in assets. 因此,我建议使用XML资源而不是资产中的XML。 You can see this CommonsWare sample project he uses the XMLPullParser to parse the xml resource.
您可以看到这个CommonsWare 示例项目,他使用XMLPullParser来解析xml资源。
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