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在python列表中使用startswith()函数

[英]Using startswith() function inside lists in python

I had the list with following strings below 我下面有以下字符串的列表

some_list = ['9196358485','9966325645','8846853128','8-4-236/2','9-6-32/45','Need to fetch some strings']

From the above strings i want only strings that does n't start with 91,9,8 but want strings starting with 8-, 9- 从上面的字符串中,我只希望不是以91,9,8开头的字符串,而是想要以8-, 9-开头的字符串

so below is my code 所以下面是我的代码

[i for i in some_list if all(not i.startswith(x) for x in ['91','8','9'])]

result : 结果

['Need to fetch some strings']

In the above by using ['91','8','9'] as the condition is deleting the strings starting with 9 and 8 which is correct, but i don't want 9-, 8- also to be removed from the list, actually my intension is if the strings starting with 9 and 8 should be ignored as above and strings starting with 9- and 8- should not be ignored , can we write two conditions in a single line with concept of taking strings starting with 8-,9- and ignoring when strings starts with 9 or 8 in the above code i had written. 在上面通过使用['91','8','9']作为条件是删除以9 and 8开头的字符串,这是正确的,但是我不希望从中删除9-, 8-列表中,实际上,我的意图是,是否应该像上面那样忽略以9 and 8开头的字符串, 9 and 8不应该忽略以9- and 8-开头的字符串,我们是否可以在一行中编写两个条件,并采用以开头的字符串8-,9-并忽略我在上面编写的代码中字符串何时以9 or 8开头。

Can anyone please let me know hoe to do this............. 任何人都可以让我知道做这件事.............

Edited code: 编辑代码:

Thanks for all of ur support if u don't think this is another question i had some actual output on which the below code is not working 感谢您的所有支持,如果您不认为这是另一个问题,我有一些实际输出,以下代码不起作用

some_list = ['Mr K V  Prasad Reddy(MD)',
 '+(91)-9849633132, 9959455935',
 '+(91)-9849633132',
 'Near NRI College,Opp Vijaya Bank,Nizam Pet Road,Nizampet,Hyderabad - 502102',
 '9196358485',
 '9966325645', 
 '8846853128',
 '8-4-236/2',
 '9-6-32/45',
 'Need to fetch some strings']

When i apply the bwlow code using regex i got following output result: 当我使用正则表达式应用bwlow代码时,得到以下输出结果:

['Mr K V  Prasad Reddy(MD)',
 '+(91)-9849633132, 9959455935',
 '+(91)-9849633132',
 'Near NRI College,Opp Vijaya Bank,Nizam Pet Road,Nizampet,Hyderabad - 502102',
 '8-4-236/2',
 '9-6-32/45',
 'Need to fetch some strings']

Actually i don't want all phone numbers from the list, so they will be in the above format sometimes starting with 91 sometimes 8 sometimes 9 实际上,我不希望列表中包含所有电话号码,因此它们的格式有时是从91开始,有时是8有时是9

How can we remove all those phone numbers from the list? 我们如何从列表中删除所有这些电话号码?

Use a regular expression: 使用正则表达式:

>>> import re
>>> [i for i in some_list if not re.match(r"[98]\B|+\(91\)", i)]
['8-4-236/2', '9-6-32/45', 'Need to fetch some strings']

\\B matches only within alphanumeric strings, so it matches between 9 and 1 but not between 9 and - . \\B仅在字母数字字符串内匹配,因此它在91之间匹配,但在9-之间不匹配。

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