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根据出现次数按升序对数组进行排序

[英]Sort array based on count of occurrences in ascending order

 原文  2012-08-07 09:29:16  8   24    java/ arrays/ sorting

问题描述

How can I arrange the elements in an array based on the number of occurrences of that value in ascending order in java. java - 如何根据该值在java中按升序出现的次数排列数组中的元素。

This is what I've tried:这是我尝试过的：

int a[]={0,0,0,1,3,3,2,1,3,5,6,0};
int b=a.length;
for(int i=0;i<b;i++) {
    for(int j=0;j<i;j++) {
        int temp;
        if( a[j]>a[i]) {
            temp=a[i];
            a[i]=a[j];
            a[j]=temp;
        }
    }
}

for(int r=0;r<a.length;r++) {
    System.out.println(a[r]);
}

24 个解决方案

解决方案1
 10  2016-04-18 13:01:43

How can I arrange the elements in an array based on the number of occurrences of that value in ascending order in java.如何在Java中根据该值的出现次数以升序排列数组中的元素。

This is what I've tried:这是我尝试过的：

int a[]={0,0,0,1,3,3,2,1,3,5,6,0};
int b=a.length;
for(int i=0;i<b;i++) {
    for(int j=0;j<i;j++) {
        int temp;
        if( a[j]>a[i]) {
            temp=a[i];
            a[i]=a[j];
            a[j]=temp;
        }
    }
}

for(int r=0;r<a.length;r++) {
    System.out.println(a[r]);
}

解决方案2
 6 已采纳  2012-08-07 10:29:14

How can I arrange the elements in an array based on the number of occurrences of that value in ascending order in java.如何在Java中根据该值的出现次数以升序排列数组中的元素。

This is what I've tried:这是我尝试过的：

int a[]={0,0,0,1,3,3,2,1,3,5,6,0};
int b=a.length;
for(int i=0;i<b;i++) {
    for(int j=0;j<i;j++) {
        int temp;
        if( a[j]>a[i]) {
            temp=a[i];
            a[i]=a[j];
            a[j]=temp;
        }
    }
}

for(int r=0;r<a.length;r++) {
    System.out.println(a[r]);
}

解决方案3
 2  2012-08-07 09:33:19

How can I arrange the elements in an array based on the number of occurrences of that value in ascending order in java.如何在Java中根据该值的出现次数以升序排列数组中的元素。

This is what I've tried:这是我尝试过的：

int a[]={0,0,0,1,3,3,2,1,3,5,6,0};
int b=a.length;
for(int i=0;i<b;i++) {
    for(int j=0;j<i;j++) {
        int temp;
        if( a[j]>a[i]) {
            temp=a[i];
            a[i]=a[j];
            a[j]=temp;
        }
    }
}

for(int r=0;r<a.length;r++) {
    System.out.println(a[r]);
}

解决方案4
 2  2018-11-05 10:20:43

How can I arrange the elements in an array based on the number of occurrences of that value in ascending order in java.如何在Java中根据该值的出现次数以升序排列数组中的元素。

This is what I've tried:这是我尝试过的：

int a[]={0,0,0,1,3,3,2,1,3,5,6,0};
int b=a.length;
for(int i=0;i<b;i++) {
    for(int j=0;j<i;j++) {
        int temp;
        if( a[j]>a[i]) {
            temp=a[i];
            a[i]=a[j];
            a[j]=temp;
        }
    }
}

for(int r=0;r<a.length;r++) {
    System.out.println(a[r]);
}

解决方案5
 1  2012-08-07 09:33:43

How can I arrange the elements in an array based on the number of occurrences of that value in ascending order in java.如何在Java中根据该值的出现次数以升序排列数组中的元素。

This is what I've tried:这是我尝试过的：

int a[]={0,0,0,1,3,3,2,1,3,5,6,0};
int b=a.length;
for(int i=0;i<b;i++) {
    for(int j=0;j<i;j++) {
        int temp;
        if( a[j]>a[i]) {
            temp=a[i];
            a[i]=a[j];
            a[j]=temp;
        }
    }
}

for(int r=0;r<a.length;r++) {
    System.out.println(a[r]);
}

解决方案6
 1  2012-08-07 09:34:51

How can I arrange the elements in an array based on the number of occurrences of that value in ascending order in java.如何在Java中根据该值的出现次数以升序排列数组中的元素。

This is what I've tried:这是我尝试过的：

int a[]={0,0,0,1,3,3,2,1,3,5,6,0};
int b=a.length;
for(int i=0;i<b;i++) {
    for(int j=0;j<i;j++) {
        int temp;
        if( a[j]>a[i]) {
            temp=a[i];
            a[i]=a[j];
            a[j]=temp;
        }
    }
}

for(int r=0;r<a.length;r++) {
    System.out.println(a[r]);
}

解决方案7
 1  2012-08-07 09:38:12

Try: 尝试： 

    int a[] = {0,0,0,1,3,3,2,1,3,5,6,0};
    Arrays.sort(a);
    System.out.println(Arrays.toString(a));

解决方案8
 1  2016-12-29 11:08:46

How can I arrange the elements in an array based on the number of occurrences of that value in ascending order in java.如何在Java中根据该值的出现次数以升序排列数组中的元素。

This is what I've tried:这是我尝试过的：

int a[]={0,0,0,1,3,3,2,1,3,5,6,0};
int b=a.length;
for(int i=0;i<b;i++) {
    for(int j=0;j<i;j++) {
        int temp;
        if( a[j]>a[i]) {
            temp=a[i];
            a[i]=a[j];
            a[j]=temp;
        }
    }
}

for(int r=0;r<a.length;r++) {
    System.out.println(a[r]);
}

解决方案9
 0  2015-08-04 04:06:37

How can I arrange the elements in an array based on the number of occurrences of that value in ascending order in java.如何在Java中根据该值的出现次数以升序排列数组中的元素。

This is what I've tried:这是我尝试过的：

int a[]={0,0,0,1,3,3,2,1,3,5,6,0};
int b=a.length;
for(int i=0;i<b;i++) {
    for(int j=0;j<i;j++) {
        int temp;
        if( a[j]>a[i]) {
            temp=a[i];
            a[i]=a[j];
            a[j]=temp;
        }
    }
}

for(int r=0;r<a.length;r++) {
    System.out.println(a[r]);
}

解决方案10
 0  2016-12-02 18:03:57

How can I arrange the elements in an array based on the number of occurrences of that value in ascending order in java.如何在Java中根据该值的出现次数以升序排列数组中的元素。

This is what I've tried:这是我尝试过的：

int a[]={0,0,0,1,3,3,2,1,3,5,6,0};
int b=a.length;
for(int i=0;i<b;i++) {
    for(int j=0;j<i;j++) {
        int temp;
        if( a[j]>a[i]) {
            temp=a[i];
            a[i]=a[j];
            a[j]=temp;
        }
    }
}

for(int r=0;r<a.length;r++) {
    System.out.println(a[r]);
}

解决方案11
 0  2017-06-25 12:21:43

How can I arrange the elements in an array based on the number of occurrences of that value in ascending order in java.如何在Java中根据该值的出现次数以升序排列数组中的元素。

This is what I've tried:这是我尝试过的：

int a[]={0,0,0,1,3,3,2,1,3,5,6,0};
int b=a.length;
for(int i=0;i<b;i++) {
    for(int j=0;j<i;j++) {
        int temp;
        if( a[j]>a[i]) {
            temp=a[i];
            a[i]=a[j];
            a[j]=temp;
        }
    }
}

for(int r=0;r<a.length;r++) {
    System.out.println(a[r]);
}

解决方案12
 0  2018-01-30 10:18:18

How can I arrange the elements in an array based on the number of occurrences of that value in ascending order in java.如何在Java中根据该值的出现次数以升序排列数组中的元素。

This is what I've tried:这是我尝试过的：

int a[]={0,0,0,1,3,3,2,1,3,5,6,0};
int b=a.length;
for(int i=0;i<b;i++) {
    for(int j=0;j<i;j++) {
        int temp;
        if( a[j]>a[i]) {
            temp=a[i];
            a[i]=a[j];
            a[j]=temp;
        }
    }
}

for(int r=0;r<a.length;r++) {
    System.out.println(a[r]);
}

解决方案13
 0  2018-08-05 12:58:46

How can I arrange the elements in an array based on the number of occurrences of that value in ascending order in java.如何在Java中根据该值的出现次数以升序排列数组中的元素。

This is what I've tried:这是我尝试过的：

int a[]={0,0,0,1,3,3,2,1,3,5,6,0};
int b=a.length;
for(int i=0;i<b;i++) {
    for(int j=0;j<i;j++) {
        int temp;
        if( a[j]>a[i]) {
            temp=a[i];
            a[i]=a[j];
            a[j]=temp;
        }
    }
}

for(int r=0;r<a.length;r++) {
    System.out.println(a[r]);
}

解决方案14
 0  2018-09-30 18:31:56

How can I arrange the elements in an array based on the number of occurrences of that value in ascending order in java.如何在Java中根据该值的出现次数以升序排列数组中的元素。

This is what I've tried:这是我尝试过的：

int a[]={0,0,0,1,3,3,2,1,3,5,6,0};
int b=a.length;
for(int i=0;i<b;i++) {
    for(int j=0;j<i;j++) {
        int temp;
        if( a[j]>a[i]) {
            temp=a[i];
            a[i]=a[j];
            a[j]=temp;
        }
    }
}

for(int r=0;r<a.length;r++) {
    System.out.println(a[r]);
}

解决方案15
 0  2018-11-15 18:33:07

How can I arrange the elements in an array based on the number of occurrences of that value in ascending order in java.如何在Java中根据该值的出现次数以升序排列数组中的元素。

This is what I've tried:这是我尝试过的：

int a[]={0,0,0,1,3,3,2,1,3,5,6,0};
int b=a.length;
for(int i=0;i<b;i++) {
    for(int j=0;j<i;j++) {
        int temp;
        if( a[j]>a[i]) {
            temp=a[i];
            a[i]=a[j];
            a[j]=temp;
        }
    }
}

for(int r=0;r<a.length;r++) {
    System.out.println(a[r]);
}

解决方案16
 0  2019-01-11 11:30:20

How can I arrange the elements in an array based on the number of occurrences of that value in ascending order in java.如何在Java中根据该值的出现次数以升序排列数组中的元素。

This is what I've tried:这是我尝试过的：

int a[]={0,0,0,1,3,3,2,1,3,5,6,0};
int b=a.length;
for(int i=0;i<b;i++) {
    for(int j=0;j<i;j++) {
        int temp;
        if( a[j]>a[i]) {
            temp=a[i];
            a[i]=a[j];
            a[j]=temp;
        }
    }
}

for(int r=0;r<a.length;r++) {
    System.out.println(a[r]);
}

解决方案17
 0  2019-01-11 12:14:11

How can I arrange the elements in an array based on the number of occurrences of that value in ascending order in java.如何在Java中根据该值的出现次数以升序排列数组中的元素。

This is what I've tried:这是我尝试过的：

int a[]={0,0,0,1,3,3,2,1,3,5,6,0};
int b=a.length;
for(int i=0;i<b;i++) {
    for(int j=0;j<i;j++) {
        int temp;
        if( a[j]>a[i]) {
            temp=a[i];
            a[i]=a[j];
            a[j]=temp;
        }
    }
}

for(int r=0;r<a.length;r++) {
    System.out.println(a[r]);
}

解决方案18
 0  2019-01-24 17:16:13

How can I arrange the elements in an array based on the number of occurrences of that value in ascending order in java.如何在Java中根据该值的出现次数以升序排列数组中的元素。

This is what I've tried:这是我尝试过的：

int a[]={0,0,0,1,3,3,2,1,3,5,6,0};
int b=a.length;
for(int i=0;i<b;i++) {
    for(int j=0;j<i;j++) {
        int temp;
        if( a[j]>a[i]) {
            temp=a[i];
            a[i]=a[j];
            a[j]=temp;
        }
    }
}

for(int r=0;r<a.length;r++) {
    System.out.println(a[r]);
}

解决方案19
 0  2019-09-09 00:45:10

How can I arrange the elements in an array based on the number of occurrences of that value in ascending order in java.如何在Java中根据该值的出现次数以升序排列数组中的元素。

This is what I've tried:这是我尝试过的：

int a[]={0,0,0,1,3,3,2,1,3,5,6,0};
int b=a.length;
for(int i=0;i<b;i++) {
    for(int j=0;j<i;j++) {
        int temp;
        if( a[j]>a[i]) {
            temp=a[i];
            a[i]=a[j];
            a[j]=temp;
        }
    }
}

for(int r=0;r<a.length;r++) {
    System.out.println(a[r]);
}

解决方案20
 0  2019-09-13 04:22:35

How can I arrange the elements in an array based on the number of occurrences of that value in ascending order in java.如何在Java中根据该值的出现次数以升序排列数组中的元素。

This is what I've tried:这是我尝试过的：

int a[]={0,0,0,1,3,3,2,1,3,5,6,0};
int b=a.length;
for(int i=0;i<b;i++) {
    for(int j=0;j<i;j++) {
        int temp;
        if( a[j]>a[i]) {
            temp=a[i];
            a[i]=a[j];
            a[j]=temp;
        }
    }
}

for(int r=0;r<a.length;r++) {
    System.out.println(a[r]);
}

解决方案21
 0  2019-11-07 19:18:29

How can I arrange the elements in an array based on the number of occurrences of that value in ascending order in java.如何在Java中根据该值的出现次数以升序排列数组中的元素。

This is what I've tried:这是我尝试过的：

int a[]={0,0,0,1,3,3,2,1,3,5,6,0};
int b=a.length;
for(int i=0;i<b;i++) {
    for(int j=0;j<i;j++) {
        int temp;
        if( a[j]>a[i]) {
            temp=a[i];
            a[i]=a[j];
            a[j]=temp;
        }
    }
}

for(int r=0;r<a.length;r++) {
    System.out.println(a[r]);
}

解决方案22
 0  2019-11-07 21:34:30

How can I arrange the elements in an array based on the number of occurrences of that value in ascending order in java.如何在Java中根据该值的出现次数以升序排列数组中的元素。

This is what I've tried:这是我尝试过的：

int a[]={0,0,0,1,3,3,2,1,3,5,6,0};
int b=a.length;
for(int i=0;i<b;i++) {
    for(int j=0;j<i;j++) {
        int temp;
        if( a[j]>a[i]) {
            temp=a[i];
            a[i]=a[j];
            a[j]=temp;
        }
    }
}

for(int r=0;r<a.length;r++) {
    System.out.println(a[r]);
}

解决方案23
 0  2021-11-12 07:52:07

Answer in python:在python中回答：

 n=input()
 arr=[int(i) for i in n.split(' ')]
 dict={}
 for i in arr:
     if(i in dict.keys()):
         dict[i]+=1
     else:
         dict[i]=1
 ans=[]
 while len(ans)<=len(arr) and dict!={}:
        maxval=min(list(dict.values()))
        keys=[]
        for key in dict.keys():
              if(dict[key]==maxval):
                   keys+=[key]
        keys=sorted(keys)
        for i in keys:
            ans+=[i]*dict[i]
            del dict[i] 
 print(ans)

解决方案24
 -1  2018-08-15 16:08:37

How can I arrange the elements in an array based on the number of occurrences of that value in ascending order in java.如何在Java中根据该值的出现次数以升序排列数组中的元素。

This is what I've tried:这是我尝试过的：

int a[]={0,0,0,1,3,3,2,1,3,5,6,0};
int b=a.length;
for(int i=0;i<b;i++) {
    for(int j=0;j<i;j++) {
        int temp;
        if( a[j]>a[i]) {
            temp=a[i];
            a[i]=a[j];
            a[j]=temp;
        }
    }
}

for(int r=0;r<a.length;r++) {
    System.out.println(a[r]);
}

解决方案25
 -1  2018-11-27 10:21:06

How can I arrange the elements in an array based on the number of occurrences of that value in ascending order in java.如何在Java中根据该值的出现次数以升序排列数组中的元素。

This is what I've tried:这是我尝试过的：

int a[]={0,0,0,1,3,3,2,1,3,5,6,0};
int b=a.length;
for(int i=0;i<b;i++) {
    for(int j=0;j<i;j++) {
        int temp;
        if( a[j]>a[i]) {
            temp=a[i];
            a[i]=a[j];
            a[j]=temp;
        }
    }
}

for(int r=0;r<a.length;r++) {
    System.out.println(a[r]);
}

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