正则表达式preg_match PHP

Question

I am trying to get contents between two curly brackets or Smarty tag. I want to get variables with smarty function only, ignoring if 's, etc.

Here are the sample string tags:

{{$variable|lower}} [should be matched]

{{$variable|escape:javascript}} [should be matched]

{{$variable|str_replace:"search":"replace"}} [should be matched]

{{if $test eq "test"}} [should NOT be matched]

{{section name=foo start=10 loop=20 step=2}} [should NOT be matched]

If I do this

preg_match_all('/{{\$?(\w+?[\W\w]*?)}}/',$str,$matches)

It gets everything within the brackets.

preg_match_all('/{{\$?(\w+?\W*?\w*?)}}/',$str,$matches);

This only gets "variable|escape".

Please help with correct regular expression.

Thanks

Answer 1

使用此正则表达式\\{\\{.*?\\|.*.+?\\}\\}

Answer 2

I could be wrong, but wouldn't simply:

preg_match_all('/\{\{(\$[^|]+)\|[^}]+\}\}/',$str,$matches);

do the trick, where $matches[1] will hold the variables. If the files contain carriage returns (windows' \\r\\n), try '/\\{\\{(\\$[^|]+)\\|[^}]+\\}\\}/s' , with the s modifier

to include matches like: {{$var}}

//{{$var|foo}} {{$varbar}} bar  as test string
preg_match_all('/\{\{(\$[^|}]+)(\|[^}]+|)\}\}/s',$str,$matches);
//shorter still:
preg_match_all('/\{\{(\$[^|}]+)\|?[^}]*\}\}/s',$str,$matches);

returns:

array (
  0 => 
  array (
    0 => '{{$var|foo}}',
    1 => '{{$varbar}}',
  ),
  1 => 
  array (
    0 => '$var',
    1 => '$varbar',
  ),
  2 => //not in the array when using the second pattern
  array (
    0 => '|foo',
    1 => '',
  ),
)