带有where子句和sum值的Mysql数据透视表

Question

SELECT * FROM ( 
select student_id, class_id,  
       sum(number*(1-abs(sign(subject-1)))) as sub1,  
       sum(number*(1-abs(sign(subject-2)))) as sub2,  
       sum(number*(1-abs(sign(subject-3)))) as sub3,  
       sum(number*(1-abs(sign(subject-4)))) as sub4,  
       sum(number*(1-abs(sign(subject-5)))) as sub5,  
       sum(number*(1-abs(sign(subject-6)))) as sub6  
from result GROUP BY student_id,class_id) m 
where class_id = '7'

its query work fine. But if the subject value is null then all student record not display in that subject. I need one fever more.

Answer 1

I don't know if there is any method using directly mysql but I can suggest you to use php

$sql = mysql_query("SELECT m.* FROM (  
select student_id, class_id,   
       sum(number*(1-abs(sign(subject-1)))) as sub1,   
       sum(number*(1-abs(sign(subject-2)))) as sub2,   
       sum(number*(1-abs(sign(subject-3)))) as sub3,   
       sum(number*(1-abs(sign(subject-4)))) as sub4,   
       sum(number*(1-abs(sign(subject-5)))) as sub5,   
       sum(number*(1-abs(sign(subject-6)))) as sub6   
from result GROUP BY student_id,class_id) m  
where m.class_id = '7'");

$row = mysql_fetch_array($sql);
$sum = 0;
for($i = 1; $i < count($row); $i++) {
    $sum += isset($row['sub' . $i]) ? $row['sub' . $i] : 0;
}