指针内存泄漏

Question

My pointer p is inside a function, will i get memory leak with this code.

for(k=0;k< 3;k++)
{

    int *p=NULL;
    int val = bBreak[k+1] - bBreak[k];

    p = new int [val+1];
    p = &buff[bBreak[k]];

    for(int i=0;i< val;i++)
        {

            cout<<"\n"<<p[i]<<endl;

        }

    }

Answer 1

Yes! You never free the memory. You should call delete/delete[] for every piece of memory you allocate with new/new[] .

Answer 2

Yes, you will

p = new int [val+1]; //allocate array on the heap
p = &buff[bBreak[k]]; //new allocated array is leaked because you lost the pointer to it
//and you are not able to call 'delete[]' to free the memory

Generally, every call to operator new should be paired with call of operator delete or delete[]

Answer 3

Yes. You must delete every memory you allocate with new .

p = new int [val+1];
p = &buff[bBreak[k]]; // here you lose track of the memory you've just allocated

If you don't want to do memory management by-hand, use a std::vector<int> .