如何从具有不同（字段x）的表中选择所有字段？ 点火枪

Question

I try this code

function catstore($id)
    {   
        $this->db->distinct();
        $this->db->select('store_id');
        $this->db->from('products');
        //$this->db->join('products','products.store_id = products.store_id');
        $this->db->where('cat_id', $id);
        $result = $this->db->get();
        return $result->result();       
    }

it produces only the distinct store_id but i want all column of the table with distinct rows based on store_id

Suggest me any option

Thanks in advance

Answer 1

You can try using group_by

function catstore($id)
{   
    $this->db->select('*');
    $this->db->from('products');
    //$this->db->join('products','products.store_id = products.store_id');
    $this->db->where('cat_id', $id);
    $this->db->group_by('store_id');
    $result = $this->db->get();
    return $result->result();       
}

I know this question is already long time ago, but one may be looking for the same problem like me, and this is how I solved it.

Answer 2

you can omit the select function altogether. If you are selecting all (*) from a table you do not need to use this function. When omitted, CodeIgniter assumes you wish to SELECT *

See http://codeigniter.com/user_guide/database/active_record.html#select

Or..

You can pass comma separated values to select function. So pass all column names separated by comma that you want to select

function catstore($id)
    {   
        $this->db->distinct();
        $this->db->select('store_id, column1, column2, cloumn3');
        $this->db->from('products');
        //$this->db->join('products','products.store_id = products.store_id');
        $this->db->where('cat_id', $id);
        $result = $this->db->get();
        return $result->result();       
    }