如何将两位加到十六进制中

Question

I have two bytes and I am setting different bits in order to get different combinations. Eg, byte 1 bit 7 and byte 2 bit 1,bit 2 makes a combination device ready. Now, I have created mask

#define C1_device_ready   (0x80 | 0x100 | 0x200)

Then I read the data and try to compare. for 1 byte I can do (data[0] & mask == mask). But how can I compute it for C1_device_ready mask where there are two bytes, data[0] and data[1]. Is it easily possible or should I do masking only in single byte. ::added::data is unsigned char data[2]

Answer 1

If data is an array of unsigned char , you could test

if ((data[0] & mask) == (mask & 0xFF) && (data[1] & mask) == ((mask >> 8) & 0xFF))

or combine the two data[i] and check

if (((data[0] | (data[1] << 8)) & mask) == mask)

Answer 2

Use

if (((data[0] | (data[1] << 8)) & mask) == mask) {
    // do something
}

Answer 3

((data[0] | (data[1]<<8)) & mask) == mask

should work. Might need to cast things as unsigned int

Answer 4

尝试：

if ((*(short *)data) & C1_device_ready)