在mysql查询中获取MAX值

Question

I have a table

       id     mid    userid    remarks
       1       2       8          7 
       2       2       8          6
       3       2       8          4 
       4       2       8          5
       5       2       8          2
       6       2       8          3
       7       2       8          7
       8       2       8          0
       9       2       8          1
       10      2       8          8

I need the last row of remark before that row. ie, remark '1'

SELECT MAX(id),mid,userid,remarks FROM sample 

Answer 1

Select Id,mid,userid,remarks from sample Where id<(select max(Id) from sample)
order by id desc limit 1

Or

Select Id,mid,userid,remarks from sample 
order by id desc limit 1 offset 1

Answer 2

Try this:

    SELECT MAX(id),mid,userid,remarks 
    FROM sample WHERE id NOT IN  (
    SELECT MAX(id) FROM sample
    )
    GROUP BY mid,userid,remarks 

EDIT

See if this works

SQL FIDDLE DEMO

Answer 3

for mysql Node.js developers especially

I was unable to get direct-value in mysql-driver for node.js ie when I run the following query

SELECT MAX(id) FROM Users

and I got the result as [RowDataPacket { MAX(id): 1 }]

I tried to retrieve the value from object console.log(MAX(id)) , but I couldn't

so I set an alias ie maxid

SELECT MAX(id) as maxid FROM Users

and got it as [RowDataPacket { maxid: 1 }]

Which I can retrieve as console.log(maxid)