使用grep的Perl regex获取子字符串

Question

4:46:31.232 AM  INFO    2012-08-13 04:46:31,232 [81-Spl/[1406]/[]]  - Adj Quantity Exceeds Paramaters. CFE 370 880N EMP NF 201209 -100 ADJOI

I need to get anything from Adj till ADJOI. "Adj Quantity Exceeds Parameters." is constant. The subsequent things always change.

I know how to do this using awk awk '{ idx=index($0,"Adj"); print substr($0,idx); }' awk '{ idx=index($0,"Adj"); print substr($0,idx); }'

Perl regex would be good. But not sure how to do this using grep with -P option

I tried the following, but it is not working grep -Po "'\\KAdj.*?(?=')"

Answer 1

May be I don't understand question, but grep -oP 'Adj.*' gives me exactly the same result as awk '{ idx=index($0,"Adj"); print substr($0,idx); }' awk '{ idx=index($0,"Adj"); print substr($0,idx); }'