[英]javascript to get php variable doesn't work
<div id="div01">01</div>
<div id="div02">02</div>
<img src="../img/logo.png" onclick="blueSky()"/>
js js
function blueSky() {
$.ajax({
type:'GET',
url: 'test.php',
success: function(respond) {
document.getElementById("div02").innerHTML=respond; // works
}
});
$("#div01").html("<?php echo $target;?>"); } // should be "abc" - doesn't work
test.php test.php
...
$target = "abc";
$("#div01").html("<?php echo $target;?>"); } // should be "abc" - doesn't work
It is not supposed to work. 它不应该工作。 Because
$target
is defined in test.php and is not within the scope of where you have the javascript .html()
call. 因为
$target
是在test.php中定义的,所以不在javascript .html()
调用的范围之内。
You can do: 你可以做:
$("#div01").html(respond);
inside the success:
attribute of your ajax call. success:
内部success:
ajax调用的属性。
Also, in test.php, I hope you are doing an echo $target
in order to get "abc" pushed back into the respond
object of blueSky()
function 另外,在test.php中,我希望您正在执行
echo $target
以便将“ abc”推回到blueSky()
函数的respond
对象中
You are using AJAX to get test.php
, so you will either have to do this: 您正在使用AJAX来获取
test.php
,因此您要么必须这样做:
test.php test.php
$target = 'abc';
echo $target;
or this: 或这个:
function blueSky() {
<?php include 'test.php'; ?>
$("#div01").html("<?php echo $target; ?>"); }
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