如何在C＃中读取XML In
[英]How to Read XML In in C#
问题描述
It may sounds a very basic question, but here it is. 
这听起来可能是一个非常基本的问题，但事实确实如此。 I have this sample XML loaded in DOM 我已将此示例XML加载到DOM中
<message from="fromvalue" to="tovalue" xml:lang="en" type="chat">
<thread>{fe422b47-9856-4404-8c35-5ff45e43ee01}</thread>
<body>Test buddy</body>
<active xmlns="http://XXXX.org/protocol/chatstates" />
</message>
This i am receiving from request body using the following piece of code 这是我使用以下代码从请求正文中收到的
StreamReader reader = new StreamReader ( HttpContext.Request.InputStream, System.Text.Encoding.UTF8 );
string sXMLRequest = reader.ReadToEnd ( );
XmlDocument xmlRequest = new XmlDocument ( );
xmlRequest.LoadXml ( sXMLRequest );
Now all i need to have is value of three things in three different variable 现在我需要拥有的是三个不同变量中的三件事的值
string bodytext = {body element inner text}
string msgfrom = {from attribute value of message element}
string msgto = {to attribute value of message element}
I am using C#, can anyone put some minutes from their precious time and guide me, will appreciate that highly 我正在使用C＃，任何人都可以从宝贵的时间中抽出一些时间来指导我，我会非常感激
4 个解决方案
解决方案1
5 已采纳 2012-08-15 14:49:40
I'd use LINQ to XML here - it's much simpler: 我将在这里使用LINQ to XML-这要简单得多：
XDocument doc = XDocument.Load(HttpContext.Request.InputStream);
string bodyText = (string) doc.Root.Element("body");
string fromAddress = (string) doc.Root.Attribute("from");
string toAddress = (string) doc.Root.Attribute("to");
That will give you a value of null for any element/attribute which isn't present. 对于任何不存在的元素/属性，这将为您提供null值。 If you're happy with a NullReferenceException instead: 如果您对NullReferenceException感到满意，请执行以下操作：
XDocument doc = XDocument.Load(HttpContext.Request.InputStream);
string bodyText = doc.Root.Element("body").Value;
string fromAddress = doc.Root.Attribute("from").Value;
string toAddress = doc.Root.Attribute("to").Value;
解决方案2
2 2012-08-15 14:49:09
You could use XDocument which is the new XML parser that was introduced in .NET 3.5: 您可以使用XDocument ，它是.NET 3.5中引入的新XML解析器：
XDocument doc = XDocument.Parse(sXMLRequest);
string bodytext = doc.Element("message").Element("body").Value;
string msgfrom = doc.Element("message").Attribute("from").Value;
string msgto = doc.Element("message").Attribute("to").Value;
解决方案3
0 2012-08-15 14:49:39
I much prefer XLINQ, however in your examples case: 我更喜欢XLINQ，但是在您的示例情况下：
XmlNode thread_node = xmlRequest.SelectSingleNode("/message/thread");
Guid thread = thread_node.InnerText;
XmlNode body_node = xmlRequest.SelectSingleNode("/message/body");
string body= body_node.InnerText;
Etc... 等等...
解决方案4
-1 2012-08-15 14:49:55
It's quite easy to serialize / deserialize between Xml and a C# class: 在Xml和C＃类之间进行序列化/反序列化非常容易：
http://www.switchonthecode.com/tutorials/csharp-tutorial-xml-serialization http://www.switchonthecode.com/tutorials/csharp-tutorial-xml-serialization
You basically create a class that holds the elements and attributes of the Xml, stick [XmlElement] and [XmlAttribute] attributes on them, and use the XmlSerializer . 您基本上可以创建一个类，其中包含Xml的元素和属性，将[XmlElement]和[XmlAttribute]属性粘贴在它们上，然后使用XmlSerializer 。
There are other options; 还有其他选择。 the XmlReader you already mentioned requires alot of work / maintenance, and is generally only used for large documents. 您已经提到的XmlReader需要大量工作/维护，并且通常仅用于大型文档。 The other answers I've seen sofar use readers of a higher abstraction level that are easy to use and do not use such a proxy class. 我见过的其他答案使用的是较高抽象级别的读者，这些读者易于使用，并且不使用此类代理类。 I guess it's a matter of preference. 我想这是偏爱的问题。
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