如何使计时器变慢？ （蟒蛇）

Question

I'm fairly new to using Python, and I'm trying to get a hit timer so that in my game when my player is hit, it needs to wait a couple seconds before he can be hit again.

I thought I could just do something like:

while hitTimer > 0:
    hitTimer -= 1

and being hit resets the counter to 10 , and requiring the counter to be > 0 to be able to be hit again, but it goes way to fast.

I tried using very small numbers like -= .00005 but that just makes my program lag bad.

How can I make it so it takes away 1 per second or something like that?

Thanks for any help.

Answer 1

In order to check for exactly 10 seconds, do this:

import time
# record when person was first hit.
previousHit = time.time()

if time.time() - previousHit > 10:
    # The rest of your logic for getting hit.
    previousHit = time.time() # Reset the timer to get the hit again.

Answer 2

Use time.clock() to check the time and time.sleep() to wait.

Never rely on CPU speed for timing code.

Answer 3

You just record the time someone was hit, using time.time() :

import time

lastHit = time.time()

And then compare the current time against lastHit :

if time.time() - lastHit > NUMBER_OF_SECONDS:
  # ... do seomthing about getting hit ...
  lastHit = time.time()