正则表达式使用前面带有特定字符的字符分割字符串

Question

I have a string which i want to split using a character preceded by a particular character

Foo:xxxxxxxxx:Bar:xxxxxxxx:FooBar:xxxxxxx

I want to split it using colon : coming after x .

I tried x: but it is removing last x .

I know that i can use this regex and then append x in each splitted string but is there a way to split this string using regex so that last x is also there.

Answer 1

Try lookbehind assertion :

(?<=x):

and your code like this:

var result = Regex.Split(inputString, "(?<=x):");

---

explain:

(?<= subexpression)
Zero-width positive lookbehind assertion.

for sample: if you apply (?<=19)\\d{2} Regex on

1851 1999 1950 1905 2003 the result is

99 , 50 , 05

Answer 2

零宽度正向后断言。

(?<=x):

Answer 3

var list = Regex.Split("Foo:xxxxxxxxx:Bar:xxxxxxxx:FooBar:xxxxxxx", "(?<=x):");

根据sbutler的使用，它使用正向后看。

Answer 4

在C＃的Regex.Split方法中使用正向Regex.Split ：

string[] substrings = Regex.Split("Foo:xxxxxxxxx:Bar:xxxxxxxx:FooBar:xxxxxxx", "(?<=x):");