如何根据内部哈希中的键值最有效地按顺序遍历哈希哈希？

Question

I've got a JSON hash of hashes returned by a website API that I want to parse and display based on a specific key's value within the internal hashes.

I can think of solutions that would achieve this, but they would take a number of lines of code and don't seem efficient. Surely there must be a way to natively in Rails, given the focus on convention over configuration. I've googled around a bit, but found nothing that covers this issue.

Sample Response from API:

[{"banner":"01197271","birthday":"1991-01-11","committee_id":1,"created_at":"2012-08-08T01:56:02-05:00","email":"me@example.com","first_name":"Dan","graduation_date":"May 2013","hometown":"San Antonio","hours_enrolled":15,"id":2,"image":{"url":null,"thumb":{"url":null},"large":{"url":null}},"invitation_accepted_at":null,"invitation_limit":null,"invitation_sent_at":null,"invitation_token":null,"invited_by_id":null,"invited_by_type":null,"last_name":"Tester","local_apt":"","local_city":"San Antonio","local_state":"Texas","local_street":"One UTSA Circle","local_zip":"78249","major":"Computer Science","permanent_apt":"","permanent_city":"","permanent_state":"","permanent_street":"One UTSA Circle","permanent_zip":"","phone":"5558813284","same_address":true,"tour_trained":false,"updated_at":"2012-08-17T03:35:26-05:00","utsa_id":"uoi431"},
{"banner":"","birthday":"1990-10-25","committee_id":null,"created_at":"2012-08-03T16:19:23-05:00","email":"you@example.com","first_name":"Test","graduation_date":null,"hometown":null,"hours_enrolled":null,"id":1,"image":{"url":null,"thumb":{"url":null},"large":{"url":null}},"invitation_accepted_at":null,"invitation_limit":null,"invitation_sent_at":null,"invitation_token":null,"invited_by_id":null,"invited_by_type":null,"last_name":"User","local_apt":"","local_city":"","local_state":"","local_street":"","local_zip":"","major":null,"permanent_apt":"","permanent_city":"","permanent_state":"","permanent_street":"","permanent_zip":"","phone":"","same_address":false,"tour_trained":false,"updated_at":"2012-08-15T10:05:54-05:00","utsa_id":""}]

Potential solution would be to go through each internal hash, determining value of relevant key value, then store, based on where the key value places it compared to already tested hashes. When complete, return.

Answer 1

Ok so if you have objects that are set up to parse this information, those objects can build themselves based off the parameters of your hash. So you could do something like this

object = MyObject.create(your_hash_parameters)

Where your_hash_parameters are the parameters that you presented in your example.

I'm not sure what would happen if there were more paramaters than your object knew what to do with, if it would still build itself or not. If that is the case, you could use the delete_if method to exclude attributes that are unwanted.

One more note, if this isn't something that you want saved to your database, and its only to display temporary information. I would set up a model with attr_accessors that represent the attributes that you are displaying.

Answer 2

如评论所述，我将创建一个ActiveResource对象并向其中添加相关方法。