[英]what is the default value of enum variable?
I have a question about enum variable in c++: 我对c ++中的枚举变量有疑问:
type enmu {
DAY1 = 1,
DAY2,
DAY3,
DAY4
} DAYS;
void main() {
DAYS days;
}
then what is the default value of days? 然后天的默认值是多少?
It's uninitialized and undefined behavior to read the value. 读取值是未初始化和未定义的行为 。
Just like saying 就像说
int x;
x
doesn't have a value until you initialize it. 在初始化之前,
x
没有值。
then what is the default value of days?`
然后天的默认值是什么?`
Like for any automatic object, the value of the days
object is indeterrminate. 与任何自动对象一样,
days
对象的值是不确定的。
Now if you declared your object with the static
specifier: 现在,如果使用
static
说明符声明对象:
static DAYS days;
Then like for any static object of an arithmetic type, the initial value would be 0
. 然后,对于任何算术类型的静态对象,初始值将为
0
。
Enumerations behave pretty much like integers, ie they don't have a well-defined default value. 枚举的行为与整数非常相似,即它们没有明确定义的默认值。 You cannot read the variable's value before initializing it without invoking undefined behavior.
在初始化变量之前,无法读取变量的值而不调用未定义的行为。
BTW, adding to the words, said before: you really do may have default value for a static enum variable. 顺便说一句,加入的话,之前说:你真的可以有一个静态变量枚举默认值。 But be carefull -- it will be 0 (as well as all other static variables).
但要小心 - 它将是0(以及所有其他静态变量)。 Consider following code:
考虑以下代码:
#include <iostream>
enum _t_test {
test_1 = 1,
test_2 = 2,
test_3 = 3,
};
static enum _t_test t;
int main()
{
using namespace std;
cout << "Value of t is: " << t;
return 0;
} }
It will print 0, but your enums are in range from 1..3. 它将打印0,但您的枚举范围为1..3。 So be aware of it.
所以要注意它。
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