C ++使用cin执行while循环

Question

Below is my do while loop with cin There a bit of problem, when user enter Fullname then press enter. The pointer will go to next line. until user press enter again, then it prompt Email address, how do i make it prompt email address right after full name is entered on my code below

Terminal Look:

Full Name: John
Email Address: some_email@gmail.com

My test.cpp code:

emailAddress= "";
fullname = "";
counter = 0;

if(department_selection!="")
{

while(fullname=="")
{
if(counter>0)
{
//so it wont print twice
cout << "Full Name: ";
}

getline(cin,fullname);
cin.clear();
cin.ignore();
counter++;
}

counter = 0;

while(emailAddress=="")
{
if(counter>0)
{
//so it wont print twice
cout << "Email Address: ";
}

getline(cin,emailAddress);
cin.clear();
cin.ignore();
counter++;
}

}// if department selection not blank

Still same issue. i need to tab enter once then it prompt for email address.

Latest Update: Manage to fix it. I make changes to the code and it is this version:

do
{
  if(counter==0)
  {
     //so it wont print twice
     cout << "Full Name: ";
  }
  if(counter>1)
  {
     //so it wont print twice
     cout << "Full Name: ";
  }

  getline(cin,fullname);
  counter++;
} while (fullname=="");

counter = 0;

do
{
  if(counter==0)
  {
     //so it wont print twice
     cout << "Email Address: ";
  }
  if(counter>1)
    {
         cout << "Email Address: ";
    }

  getline(cin,emailAddress);
  counter++;
} while (emailAddress=="");

Answer 1

Instead of if(counter>0) use if(counter==0)

My working test app:

int counter = 0;
string fullname, emailAddress;
do
{
  if(counter==0)
  {
     //so it wont print twice
     cout << "Full Name: ";
  }

  getline(cin,fullname);
  counter++;
} while (fullname=="");

counter = 0;

do
{
  if(counter==0)
  {
     //so it wont print twice
     cout << "Email Address: ";
  }

  getline(cin,emailAddress);
  counter++;
} while (emailAddress=="");

Answer 2

Check for length and then @.

 do
    {
    ...
    }while(fullname.length()<2);

    do
    {
    ...
    }while(emailAddress.length()<3||emailAddress.find("@")==string::npos);

Answer 3

使用clear（）和ignore（）函数也可以忽略已存储在输入中的单词

Answer 4

Define a function to avoid repeating code:

#include <iostream>
#include <string>
#include <limits>

using namespace std;

string get_input(const std::string& prompt)
{
    string temp;
    cout << prompt;
    while (!getline(cin, temp) || temp.empty()) {
        cin.clear();
        cin.ignore(numeric_limits<streamsize>::max(), '\n');
    }
    return temp;
}

int main()
{
    string fullname = get_input("Full Name: ");
    string email = get_input("Email Adress: ");
}