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如何在Matlab中将函数作为参数传递

[英]How to pass a function as argument in Matlab

I have this function defined in a m-file: 我在m文件中定义了此功能:

function[it,xvect,xdif,fx]=bisez(a,b,nmax,toll,fun)
it=-1;
xvect=[];
xdif=[];
fx=[];
err=toll+1;

while(it<nmax && err>toll)
x=(b+a)/2;
  if(fun(x)==0)
    err=0;
  else
    err=abs(b-a)/2;
  end
it=it+1;
xvect=[xvect;x];
xdif=[xdif;err];
fx=[fx:fun(x)];
  if(fun(x)*fun(a)>0)
    a=x;
  else
    b=x;
  end;
end;
if(it<nmax)
  fprintf('Convergence computed at step k:%d\n',it);
else
  fprinf('Iteration limit reached: %d\n',it);
end
  fprintf('Computed root: %-12.8f\n',xvect(it+1));
return

Then if I try to invoke it with these commands: 然后,如果我尝试使用以下命令调用它:

fun=@(x)exp(x);
a=1;
b=1.5;
nmax=1000;
toll=2;
bisez(a,b,nmax,toll,fun)

I get this error: 我收到此错误:

??? Undefined function or method 'bisez' for input arguments of type 'function_handle'.

What am I missing? 我想念什么?

PS: I'm using Matlab 2007b PS:我正在使用Matlab 2007b

It appears it is not in your PATH when you run it. 在运行它时,它似乎不在您的PATH中。

If I run it from my PATH I get: 如果从PATH运行它,则会得到:

>> bisez(a,b,nmax,toll,fun)
   Convergence computed at step k:0
   Computed root: 1.25000000  

   ans =

        0

Outside of my PATH: 在我的路径之外:

>> bisez(a,b,nmax,toll,fun)
   Undefined function 'bisez' for input arguments of type 'function_handle'.

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