[英]How can I get all text nodes from XML file
I want to get all text nodes from an XML file. 我想从XML文件中获取所有文本节点。
How can I do this? 我怎样才能做到这一点?
Example Input: 示例输入:
<root>
<slide>
<Image>hi</Image>
<ImageContent>this</ImageContent>
<Thumbnail>is</Thumbnail>
<ThumbnailContent>A</ThumbnailContent>
</slide>
</root>
Expected Output: 预期产出:
hi this is A
The only solution (so far) to enumerate all text nodes in any xml, regardless of its structure: 唯一的解决方案(到目前为止)枚举任何xml中的所有文本节点,无论其结构如何:
string input = @"
<root>
<slide>
<Image>hi</Image>
<ImageContent>this</ImageContent>
<Thumbnail>is</Thumbnail>
<ThumbnailContent>A</ThumbnailContent>
</slide>
</root>";
foreach (XText text in (IEnumerable)XDocument.Parse(input).XPathEvaluate("//*/text()"))
{
Console.WriteLine(text.Value);
}
EDIT: if you want to load xml from file then use XDocument.Load
instead. 编辑:如果你想从文件加载xml然后使用XDocument.Load
。
This code will print the inner text of all xml nodes which doesnt have a child: 此代码将打印没有子项的所有xml节点的内部文本:
static void Main(string[] args)
{
XmlDocument x = new XmlDocument();
x.Load("exp.xml");
PrintNode(x.DocumentElement);
}
private static void PrintNode(XmlNode x)
{
if (!x.HasChildNodes)
Console.Write(string.Format("{0} ", x.InnerText));
for (int i = 0; i < x.ChildNodes.Count; i++)
{
PrintNode(x.ChildNodes[i]);
}
}
On your example XML it will result in the output you want :) 在您的示例XML上,它将产生您想要的输出:)
You can try this: 你可以试试这个:
string input = @"
<root>
<slide>
<Image>hi</Image>
<ImageContent>this</ImageContent>
<Thumbnail>is</Thumbnail>
<ThumbnailContent>A</ThumbnailContent>
</slide>
</root>";
XDocument doc = XDocument.Parse(input);
//You can also load data from file by passing file path to Load method
//XDocument doc = XDocument.Load("Data.xml");
foreach(var slide in doc.Root.Elements("slide"))
{
var words = slide.Elements().Select(el => el.Value);
string s = String.Join(" ", words.ToArray());
}
This will work 这会奏效
static void Main(string[] args)
{
XDocument xmlSkuDescDoc = XDocument.Parse
(@"<root>
<slide>
<Image>hi</Image>
<ImageContent>this</ImageContent>
<Thumbnail>is</Thumbnail>
<ThumbnailContent>A</ThumbnailContent>
</slide>
</root> "
);
var result = (from data in xmlSkuDescDoc.Descendants("slide")
select data).Elements().Select(i => i.Value).Aggregate((a, b) => a + " " + b);
Console.ReadKey();
}
NB~ use XDocument.Load(filename)
if loading from file NB~如果从文件加载,请使用XDocument.Load(filename)
eg 例如
string fileName = @"D:\MyXml.xml";
XDocument xmlSkuDescDoc = XDocument.Load(filename);
.... and the rest follows as shown above ......其余部分如上所示
It can be done using XDocument
class (LINQ to XML). 它可以使用XDocument
类(LINQ to XML)完成。 Assuming that you have exactly one slide element: 假设您只有一个幻灯片元素:
Using plain XDocument
navigation: 使用普通的XDocument
导航:
var doc = XDocument.Load("file path here");
if (doc.Root == null)
throw new ArgumentException(); // No root node!
var slideElement = doc.Root.Element("slide");
if (slideElement == null)
throw new ArgumentException(); // No slide node!
var values = string.Join(" ", slideElement.Elements().Select(element => element.Value));
Using XPath node selection: 使用XPath节点选择:
var doc = XDocument.Load("file path here");
var slideElements = doc.XPathSelectElements("root/slide/*");
var values = string.Join(" ", slideElements.Select(element => element.Value));
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