SQL Server排序规则冲突-创建视图

Question

i am trying to create a View in a Database A, that is filled by a select from the Database B and i am having a collation conflict, to be more exactly , its between ( Latin1_General_CI_AS" and "Latin1_General_BIN ). WHere(in the code) i need to put the collate?

Best Regards.

The code is here:

CREATE VIEW [dbo].[CML_SDG_MENSAL_ESTOQUE]
AS

select  
SUM(dw_fato_faturmes.val_fatur) val_fatur, 
SUM(dw_fato_faturmes.val_receita) val_receita, 
SUM(dw_fato_faturmes.qtd_bonif_item) qtd_bonif_item, 
SUM(dw_fato_faturmes.val_bonif_fatur) val_bonif_fatur,
SUM(dw_fato_faturmes.val_bonif_receita) val_bonif_receita,
SUM(dw_fato_faturmes.val_devol_fatur) val_devol_fatur,
SUM(dw_fato_faturmes.val_devol_receita) val_devol_receita,
DW_DIM_PRODUTO.B1_CODDB B1_CODDB,
dw_fato_faturmes.cod_produto cod_produto, 
SUM(dw_fato_faturmes.qtd_estoque) qtd_estoque, 
SUM(dw_fato_faturmes.qtd_devol) qtd_devol, 
SUM(dw_fato_faturmes.qtd_item) qtd_item, 
SUM(dw_fato_faturmes.qtd_meta) qtd_meta,
SUM(dw_fato_faturmes.qtd_pedido) qtd_pedido,
SUM(dw_fato_faturmes.qtd_item)+
    SUM(dw_fato_faturmes.qtd_bonif_item)+
    SUM(dw_fato_faturmes.qtd_devol) venda_liquida
(SUM(dw_fato_faturmes.qtd_item)
     +SUM(dw_fato_faturmes.qtd_bonif_item)
    +SUM(dw_fato_faturmes.qtd_devol))
    +SUM(dw_fato_faturmes.qtd_pedido) venda___pedido
FROM 
logixbi.dbo.dw_fato_faturmes dw_fato_faturmes, 
logixbi.dbo.DW_DIM_CLIENTE DW_DIM_CLIENTE, 
DW_DIM_EMPRESA DW_DIM_EMPRESA, 
logixbi.dbo.DW_DIM_MARCA DW_DIM_MARCA, 
logixbi.dbo.DW_DIM_PRODUTO DW_DIM_PRODUTO, 
logixbi.dbo.DW_DIM_REPRESENTANTE DW_DIM_REPRESENTANTE

where 
DW_DIM_EMPRESA.SM0_FILIAL=dw_fato_faturmes.filial and
DW_DIM_MARCA.BM_GRUPO=dw_fato_faturmes.grupo and
DW_DIM_PRODUTO.B1_COD=dw_fato_faturmes.cod_produto and
DW_DIM_REPRESENTANTE.A3_COD=dw_fato_faturmes.vendedor and
DW_DIM_CLIENTE.A1_COD=dw_fato_faturmes.cliente and
DW_DIM_CLIENTE.A1_LOJA=dw_fato_faturmes.loja

group by DW_DIM_PRODUTO.B1_CODDB,dw_fato_faturmes.cod_produto

Answer 1

In order to find wich column has wich collation use this snippet:

SELECT name, collation_name
  FROM sys.columns
  WHERE OBJECT_ID IN (SELECT OBJECT_ID
                        FROM sys.objects
                       WHERE type = 'U'
                         AND name = 'your_table_name'
                      )
    AND name = 'your_column_name'

Once you find the columns try this:

column_1 COLLATE your_collation = column_2 COLLATE your_collation

It is better to stick to a single collation globally. Otherwise you will have problems. Here is a snippet that will give you all the columns on your database with a COLLATION different than the one in the database

SELECT [TABLE_NAME] = OBJECT_NAME([id]),
       [COLUMN_NAME] = [name],
       [COLLATION_NAME] = collation
  FROM syscolumns
 WHERE collation <> 'your_database_collation_type'
   AND collation IS NOT NULL
   AND OBJECTPROPERTY([id], N'IsUserTable')=1

Answer 2

Where to put it depends on where the conflict is.

I'd suggest on the joins

ie

DW_DIM_EMPRESA.SM0_FILIAL COLLATE Latin1_General_CI_AS =dw_fato_faturmes.filial COLLATE Latin1_General_CI_AS 

Answer 3

这是由于不同归类类型之间的操作而发生的，因此请尝试使用此语句进行比较。

ColumnA = ColumnB collate database_default

Answer 4

尝试在where子句中的所有字符匹配条件中使用此命令：

colnameA COLLATE Latin1_General_CI_AS = columnnameB COLLATE Latin1_General_CI_AS