列出每个键具有多个值的字典

Question

I have a Python list which holds pairs of key/value :

list = [ {'A': {'value': '2h25m'}, 'B': {'value': '2:45 AM'}, 
          'C': {'value': 'LAX'}, 'D': {'value': '+0100'}} ]

I want to convert the list into a dictionary like this:

d = {'A': '2h25m', 'B': '2:45 AM', 'C': 'LAX', 'D':'+0100'}

Thks

Answer 1

lst = [ {'A': {'value': '2h25m'}, 'B': {'value': '2:45 AM'}, 'C': {'value': 'LAX'}, 'D': {'value': '+0100'}} ]
my_dict = dict([(k, v['value']) for k, v in lst[0].items()])

First of all, don't use list as a variable name as it shadows the built-in list() function. Furthermore, as you can see, I've used a list comprehension to built a list with (key, value) tuples which can then be passed to the dict() function to create the desired dictionary.

As mgilson points out, you can also use a generator expression instead of a list comprehension:

lst = [ {'A': {'value': '2h25m'}, 'B': {'value': '2:45 AM'}, 'C': {'value': 'LAX'}, 'D': {'value': '+0100'}} ]
my_dict = dict((k, v['value']) for k, v in lst[0].items())

Answer 2

You can use a dict comprehension in later versions of Python:

In [30]: lst = [ {'A': {'value': '2h25m'}, 'B': {'value': '2:45 AM'}, 
    ...:           'C': {'value': 'LAX'}, 'D': {'value': '+0100'}} ]

In [31]: {k: v['value'] for k, v in lst[0].items()}
Out[31]: {'A': '2h25m', 'B': '2:45 AM', 'C': 'LAX', 'D': '+0100'}