[英]android: Set link with <a href> in TextView
I create a TextView dynamically and want to set the text as linkable. 我动态创建TextView并希望将文本设置为可链接。 Text value is " Google ".
文字值为“ Google ”。 I referred to internet & blogs like this, which shows the same way, but I couldn't produce the expected results.
我提到了像这样的互联网和博客,它以同样的方式显示,但我无法产生预期的结果。
I tried different ways, but the output I see is the whole text with text only. 我尝试了不同的方法,但我看到的输出是仅包含文本的整个文本。 The code I have tried with is :
我试过的代码是:
TextView tv1 = new TextView(this);
tv1.setLayoutParams(textOutLayoutParams);
// Make Linkable
tv1.setMovementMethod(LinkMovementMethod.getInstance());
tv1.setText(Html.fromHtml(l.getLeftString()));
/*SpannableString s = new SpannableString(l.getLeftString());
Linkify.addLinks(s, Linkify.WEB_URLS);
tv1.setText(s);
tv1.setMovementMethod(LinkMovementMethod.getInstance());
*/
dialogLayout.addView(tv1);
In my output I see " Google " and no link. 在我的输出中,我看到“ 谷歌 ”,没有链接。 I also tried Clean project & building it again, but no success.
我也尝试过清洁项目并再次构建它,但没有成功。 I am looking to see only "Google" as underlined with blue color (as default) and on clicking Google, the browser open with http://google.com .
我希望只有“Google”标有蓝色下划线(默认情况下),点击Google后,浏览器会打开http://google.com 。
What is lacking in my code to get the output ? 我的代码缺少什么来获得输出? BTW For REF : I use 64bit Win 7, Java, Eclipse, Android API 8-2.2
BTW For REF:我使用64位Win 7,Java,Eclipse,Android API 8-2.2
Any help is highly appreciated. 任何帮助都非常感谢。
I finally got it working using the following code : 我终于使用以下代码了解它:
TextView tv1 = new TextView(this);
tv1.setLayoutParams(textOutLayoutParams);
tv1.setText(Html.fromHtml("<a href=\""+ l.getRightString() + "\">" + l.getLeftString() + "</a>"));
tv1.setClickable(true);
tv1.setMovementMethod (LinkMovementMethod.getInstance());
dialogLayout.addView(tv1);
l.getRightString() - contains a url like http:\\www.google.com l.getLeftString() - contains text for the url like "Go to Google" l.getRightString() - 包含一个像http:\\ www.google.com l.getLeftString()的网址 - 包含“Go to Google”等网址的文字
RESULTS : Text "Go to Google" on my dialog with blue color and underlined, and on clicking it the browser opens up and shwows the respective page. 结果:在我的对话框中用蓝色和带下划线的文本“转到谷歌”,点击它后,浏览器打开并显示相应的页面。 On returning/Exiting the browser it again comes to the app from the state where it had left.
在返回/退出浏览器时,它再次从它离开的状态进入应用程序。
Hope this helps. 希望这可以帮助。
Save your html in a string 将html保存在字符串中
<string name="link"><a href="http://www.google.com">Google</a></string>
Set textview ID to to 将textview ID设置为
textViewLinkable
In main activity use following code: 在主要活动中使用以下代码:
((TextView) findViewById(R.id.textViewLinkable)).setMovementMethod(LinkMovementMethod.getInstance());
((TextView) findViewById(R.id.textViewLinkable)).setText(Html.fromHtml(getResources().getString(R.string.link)));
Here is my simple implementation tested up to Android N. 这是我在Android N上测试的简单实现。
String termsText = "By registering, you are agree to our";
String termsLink = " <a href=https://www.yourdomain.com/terms-conditions.html >Terms of Service</a>";
String privacyLink = " and our <a href=https://www.yourdomain.com/privacy-policy.html >Privacy Policy</a>";
String allText = termsText + termsLink + privacyLink;
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.N) {
((TextView) findViewById(R.id.text_terms_conditions)).setMovementMethod(LinkMovementMethod.getInstance());
((TextView) findViewById(R.id.text_terms_conditions)).setText(Html.fromHtml(allText, Html.FROM_HTML_MODE_LEGACY));
}
else {
((TextView) findViewById(R.id.text_terms_conditions)).setMovementMethod(LinkMovementMethod.getInstance());
((TextView) findViewById(R.id.text_terms_conditions)).setText(Html.fromHtml(allText));
}
I was also facing the same issue I resolved using following 我也面临着我使用以下解决的相同问题
String str_text = "<a href=http://www.google.com >Google</a>";
TextView link;
link = (TextView) findViewById(R.id.link);
link.setMovementMethod(LinkMovementMethod.getInstance());
link.setText(Html.fromHtml(str_text));
for changing the link color to blue use 用于将链接颜色更改为蓝色使用
link.setLinkTextColor(Color.BLUE);
txtview.setMovementMethod(LinkMovementMethod.getInstance());
Pass this statement to your textview, and in string.xml set an string as 将此语句传递给textview,并在string.xml中将字符串设置为
<string name="txtCredits"> <a href="http://www.google.com"></a></string>
Now pass this string name " android:text="@string/txtCredits" to your xml class where the txtview is there . 现在将此字符串名称“android:text =”@ string / txtCredits“传递给txtview所在的xml类。
use this code autolink-java On GitHub 在GitHub上使用此代码autolink-java
like this 像这样
private String getLink(String string){
LinkExtractor linkExtractor = LinkExtractor.builder()
.linkTypes(EnumSet.of(LinkType.URL)) // limit to URLs
.build();
Iterable<Span> spans = linkExtractor.extractSpans(string);
StringBuilder sb = new StringBuilder();
for (Span span : spans) {
String text = string.substring(span.getBeginIndex(), span.getEndIndex());
if (span instanceof LinkSpan) {
// span is a URL
sb.append("<a href=\"");
sb.append(text);
sb.append("\">");
sb.append(text);
sb.append("</a>");
} else {
// span is plain text before/after link
sb.append(text);
}
}
return sb.toString(); // "wow <a href=\"http://test.com\">http://test.com</a> such linked"
}
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