获取闰年日期php

Question

I want to convert 59 to 2012-feb-29. I already know current year is 2012. I try following code. but it give 2012-mar-01.

$string = '59 2012';
$date1 = date_create_from_format('z Y', $string);
$date_time = date_format($date1, 'Y-m-d');
echo $date_time;

Answer 1

Try:

echo date('Y-m-d', strtotime(date('Y-01-01')) + 59 * 86400);

Update:

The problem in your code is because z is starting from 0 , so you need to minus 1 .

$date1 = date_create_from_format('z', 59 - 1);
$date_time = date_format($date1, 'Y-m-d');
echo $date_time;

Answer 2

您可以改用strtotime() ：

echo date('Y-m-d', strtotime('2012-01 +59 day'));

Answer 3

I've encountered this issue before and this is the solution I came up to:

/**
 * Get date if leap year
 * 
 * @param int $year z date format
 * @param int $date Y date format
 * 
 * @return object|null
 */
private function getLeapYearDate($year, $date)
{
    if ($date >= 1 && $date <= 59) {
        return date_create_from_format('z', $date - 1);
    } else if ($date == 60) {
        return date_create($year . '-02-29');
    } else if ($date >= 61 && $date <= 365) {
        return date_create_from_format('z', $date - 2);
    } else if ($date == 366) {
        return date_create($year . '-12-31');
    }

    return null;
}

Hope this helps! Have a good day...