打破JavaScript循环

Question

I have following code to use google images search API:

google.load('search', '1');   
    function searchComplete(searcher) {
      // Check that we got results
      if (searcher.results && searcher.results.length > 0) {
        // Grab our content div, clear it.
        var contentDiv = document.getElementById('contentimg');
        contentDiv.innerHTML = '';

        // Loop through our results, printing them to the page.
        var results = searcher.results;
        for (var i = 1; i < results.length; i++) {
          // For each result write it's title and image to the screen
          var result = results[i];
          var imgContainer = document.createElement('div');



          var newImg = document.createElement('img');
          // There is also a result.url property which has the escaped version
          newImg.src = result.tbUrl;


          imgContainer.appendChild(newImg);

          // Put our title + image in the content
          contentDiv.appendChild(imgContainer);

The problem is, it gives me 3 image results. How to break a loop and show only the 1st one instead of 3 images? if I change for (var i = 1; i < results.length; i++) to for (var i = 3; i < results.length; i++) it shows only one image, but image shown is the 3rd one and I need to show 1st one :) Please advice

Answer 1

Don't use a for loop at all. Just replace all instances of i with 0.

google.load('search', '1');   
    function searchComplete(searcher) {
      // Check that we got results
      if (searcher.results && searcher.results.length > 0) {
        // Grab our content div, clear it.
        var contentDiv = document.getElementById('contentimg');
        contentDiv.innerHTML = '';

        var result = searcher.results[0];

        var imgContainer = document.createElement('div');

        var newImg = document.createElement('img');
        // There is also a result.url property which has the escaped version
        newImg.src = result.tbUrl;

        imgContainer.appendChild(newImg);

        // Put our title + image in the content
        contentDiv.appendChild(imgContainer);

0 means the first item returned (almost all number sequences in programming start at 0!) so all other results will be ignored.

Answer 2

use break statement . It will terminate the loop once the image is found and hence you will have only the first one.

      for (var i = 1; i < results.length; i++) {
      // For each result write it's title and image to the screen
      var result = results[i];
      var imgContainer = document.createElement('div');



      var newImg = document.createElement('img');
      // There is also a result.url property which has the escaped version
      newImg.src = result.tbUrl;


      imgContainer.appendChild(newImg);

      // Put our title + image in the content
      contentDiv.appendChild(imgContainer);
       //Berore the end of the loop
      if(i==1)
      {
      break;
      }
   }

Answer 3

When you only want one element, you don't need a for loop. You can access the first element of an array with

result = results[0];

Arrays are zero-based. So when it contains three images, the images are named results[0], results[1] and results[2].