数组和for循环

Question

I wrote this code. I am new to Java and willing to develop my skills,so I wrote this code,in order to learn Arrays,one developer suggested HashSet,I am looking forward for new suggestions.

import java.io.*;
public class dictionary 
{    
    public static void main(String args[])
    {
        String[] MyArrayE=new String[5];
        String[] MyArrayS=new String[5];


        MyArrayE[0]="Language";
        MyArrayE[1]="Computer";
        MyArrayE[2]="Engineer";
        MyArrayE[3]="Home";
        MyArrayE[4]="Table";


        MyArrayS[0]="Lingua";
        MyArrayS[1]="Computador";
        MyArrayS[2]="Ing.";
        MyArrayS[3]="Casa";
        MyArrayS[4]="Mesa";

            System.out.println("Please enter a word");
            BufferedReader br = new BufferedReader(new InputStreamReader(System.in)); 
          String word= null;
           try {
             word= br.readLine();
           } catch (IOException e) {
             System.out.println("Error!");
             System.exit(1);
           }
           System.out.println("Your word is " + word);


        for(int i=0; i<MyArrayE.length; i++)  
        {
            if(word.equals(MyArrayS[i]))
            {
                System.out.println(MyArrayE[i]);

            }
        }   

    }
}

My Question: What about if the user inputs a word not in MyArrayS, I want to check that and print a statement like "Word does not exist".

I think that it might look like:

if(word!=MyArrayS)
{
System.out.println("Word does not exist");
}

Thanks

Answer 1

您可以简单地使用.Contains（String）方法来确定单词是否包含在数组中。

Answer 2

You have to check every element of the array to see that it's not there. So your code would actually look like:

int c;
boolean found = false;

for(c = 0;c < MyArrayS.length;c++) {
  if(MyArrayS.compareTo(word) == 0) {
   found = true;
  }
}

if(!found) {
  System.out.println("Word does not exist");
}