[英]Sql query to derive a column value based on the entry in another table
I have a person table with fields id
, email
. 我有一个人表,包含字段
id
, email
。
And a subscription table with fields: person_id
, category_id
. 以及具有以下字段的订阅表:
person_id
, category_id
。
If a person is subscribed subscription table will have at-least one entry in the table. 如果一个人被订阅,则订阅表将在该表中至少有一个条目。
I want to query person table with the 3rd column having 1 or 0 depending on whether person is subscribed or not. 我想查询人员表,其第三列的值为1或0,具体取决于人员是否已订阅。
select p.id, p.email , [is_subscribed]
from person p
is_subscribed
should be 1 if there is an entry in the subscription table else should be 0. 如果订阅表中有一个条目,则
is_subscribed
应该为1,否则应为0。
How can I achieve the above ? 如何实现以上目标?
Using a LEFT JOIN on subscription & a count (in a case of several subscriptions) 在订阅和计数上使用LEFT JOIN(如果有多个订阅)
SELECT p.id,p.email,IF(COUNT(s.category_id)>0,1,0) as is_subscribed
FROM
person as p
LEFT JOIN subscription as s ON s.person_id=p.id
GROUP BY p.id
select distinct p.id, p.email, ifnull(sign(subscription.id),0) as is_subscribed
from
person
left join subscriptions
on person.id = subscriptions.person_id
SELECT p.`id` , p.`email` , IF(COUNT(s.`id`)>0,1,0) AS count
FROM `person` p
LEFT JOIN `subscription` s ON s.`person_id` = p.`id`
select distinct person.id, person.email, cast((select count(id) from sub where id=1) as bit) from tab, sub where tab.id=1;
This is an MS SQL server query. 这是一个MS SQL服务器查询。 Make necessary changes for mysql.
对mysql进行必要的更改。
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