[英]Delete everything after part of a string
I have a string that is built out of three parts.我有一个由三部分组成的字符串。 The word I want the string to be (changes), a seperating part (doesn't change) and the last part which changes.
我希望字符串是(更改),一个单独的部分(不更改)和更改的最后一部分。 I want to delete the seperating part and the ending part.
我想删除分隔部分和结尾部分。 The seperating part is " - " so what I'm wondering is if theres a way to delete everything after a certaint part of the string.
分隔部分是“ - ”,所以我想知道是否有办法删除字符串的某个部分之后的所有内容。
An example of this scenario would be if I wanted to turn this: "Stack Overflow - A place to ask stuff" into this: "Stack Overflow".这种情况的一个例子是,如果我想把这个:“Stack Overflow - A place to ask stuff”变成这个:“Stack Overflow”。 Any help is appreciated!
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For example, you could do:例如,你可以这样做:
String result = input.split("-")[0];
or要么
String result = input.substring(0, input.indexOf("-"));
(and add relevant error handling) (并添加相关的错误处理)
apache commons StringUtils 提供了一个substringBefore方法
StringUtils.substringBefore("Stack Overflow - A place to ask stuff", " - ")
You can use this你可以用这个
String mysourcestring = "developer is - development";
String substring = mysourcestring.substring(0,mysourcestring.indexOf("-"));
it would be written "developer is -"它会写成“开发者是——”
Use the built-in Kotlin substringBefore
function ( Documentation ):使用内置的 Kotlin
substringBefore
函数( 文档):
var string = "So much text - no - more"
string = string.substringBefore(" - ") // "So much text"
It also has an optional second param, which is the return value if the delimiter is not found.它还有一个可选的第二个参数,如果没有找到分隔符,它是返回值。 The default value is the original string
默认值为原始字符串
string.substringBefore(" - ", "fail") // "So much text"
string.substringBefore(" -- ", "fail") // "fail"
string.substringBefore(" -- ") // "So much text - no - more"
Perhaps thats what you are looking for:也许这就是你要找的:
String str="Stack Overflow - A place to ask stuff";
String newStr = str.substring(0, str.indexOf("-"));
I created Sample program for all the approches and SubString
seems to be fastest one.我为所有方法创建了示例程序,
SubString
似乎是最快的程序。
Using builder : 54
Using Split : 252
Using Substring : 10
Below is the sample program code下面是示例程序代码
for (int count = 0; count < 1000; count++) {
// For JIT
}
long start = System.nanoTime();
//Builder
StringBuilder builder = new StringBuilder(
"Stack Overflow - A place to ask stuff");
builder.delete(builder.indexOf("-"), builder.length());
System.out.println("Using builder : " + (System.nanoTime() - start)
/ 1000);
start = System.nanoTime();
//Split
String string = "Stack Overflow - A place to ask stuff";
string.split("-");
System.out.println("Using Split : " + (System.nanoTime() - start)
/ 1000);
//SubString
start = System.nanoTime();
String string1 = "Stack Overflow - A place to ask stuff";
string1.substring(0, string1.indexOf("-"));
System.out.println("Using Substring : " + (System.nanoTime() - start)
/ 1000);
return null;
Clean way to safely remove until a string, and keep the searched part if token may or may not exist.安全删除直到字符串的干净方法,如果令牌可能存在或可能不存在,则保留搜索的部分。
String input = "Stack Overflow - A place to ask stuff";
String token = " - ";
String result = input.contains(token)
? token + StringUtils.substringBefore(string, token)
: input;
// Returns "Stack Overflow - "
Apache StringUtils functions are null-, empty-, and no match- safe
Apache StringUtils函数是空、空和无匹配安全的
这将做你需要的:
newValue = oldValue.substring(0, oldValue.indexOf("-");
String line = "deltaasm:/u01/app/oracle/product/11.2.0/dbhome_1:N # line addred by agent";
String rep = "deltaasm:";
String after = "";
String pre = ":N";
String aft = "";
String result = line.replaceAll(rep, after);
String finalresult = result.replaceAll(pre, aft);
System.out.println("Result***************" + finalresult);
String str = "deltaasm:/u01/app/oracle/product/11.2.0/dbhome_1:N # line addred by agent";
String newStr = str.substring(0, str.indexOf("#"));
System.out.println("======" + newStr);
you can my utils method this action..你可以用我的 utils 方法这个动作..
public static String makeTwoPart(String data, String cutAfterThisWord){
String result = "";
String val1 = data.substring(0, data.indexOf(cutAfterThisWord));
String va12 = data.substring(val1.length(), data.length());
String secondWord = va12.replace(cutAfterThisWord, "");
Log.d("VAL_2", secondWord);
String firstWord = data.replace(secondWord, "");
Log.d("VAL_1", firstWord);
result = firstWord + "\n" + secondWord;
return result;
}`
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