jQuery脚本在Google Chrome中不起作用

Question

As odd as it may seem I have a part of my script that looks like this... php is controlling access to my jQuery function; please excuse the fact that there maybe some redundant code here, but allow me to explain the main issue here.

Here is a code excerpt of php:

<?php
        if($user_info['ACTIVE'] == 'Y')
            {
                require("jQuery/main_function.js");
                require("edit_profile.php");
            }elseif(!isset($_GET['resend']))
            {
                echo '<div id="profile_info"><p>In order to modify or setup your seller profile your account must be activated.<br />
                Check your email; if you did not receive an email, <a href="profile.php?resend">Click here</a> to have another one dispatched.</p>';
                echo '<p>You can however complete your contact information <a href="user_contact.php">here</a>';
            }

As you can see in the php code, if the user is active, as determined from a database call, it will require main_function.js in the html, thus dropping this:

<script type="text/javascript">
function option_click(elementId)
    {
        $(document).ready(function(){
            alert('testing1');
            var defaultString = "Upload";
            var elementNum = elementId.substr(elementId.length-1, 1);
            switch($('#'+elementId).val())
            {
                case 'Video':
                {
                    alert('testing in chrome');
                    $('.set_time'+elementNum).prop('type', 'hidden');
                    $('.product_upload'+elementNum).prop('type', 'file');
                    $('.content_upload'+elementNum).html(defaultString + ' a ' + 'video file:');
                    break;  
                }
                case 'Time':
                {
                    $('.content_upload'+elementNum).html('How much time?');
                    $('.product_upload'+elementNum).prop('type', 'hidden');
                    $('.set_time'+elementNum).prop('type', 'text');
                    break;
                }
                case 'Music/Audio':
                {
                    $('.set_time'+elementNum).prop('type', 'hidden');
                    $('.product_upload'+elementNum).prop('type', 'file');
                    $('.content_upload'+elementNum).html(defaultString + ' a ' + 'music file');
                    break;
                }
                case 'Ebook':
                {
                    $('.set_time'+elementNum).prop('type', 'hidden');
                    $('.product_upload'+elementNum).prop('type', 'file');
                    $('.content_upload'+elementNum).html(defaultString + ' an ' + 'ebook file');
                    break;  
                }
                case 'Tutorial/Docs':
                {
                    $('.set_time'+elementNum).prop('type', 'hidden');
                    $('.product_upload'+elementNum).prop('type', 'file');
                    $('.content_upload'+elementNum).html(defaultString + ' a ' + 'tutorial file');  
                    break;
                }
            }
        });
    }
</script>

in the middle of my code...

Works fine in all browsers except google chrome? Why?

Answer 1

You are swirching option's value like

switch($('#'+elementId).val())

but in your element (option) I didn't see any value assigned (from the comment you provided)

<option id="video0" onclick="option_click(this.id)">Video</option>

Update:

Your approach (not working in Chrome)

<select>
   <optgroup label="Swedish Cars">
       <option id="volvo" onclick="option_click(this.id)">Volvo</option>
       <option id="saab" onclick="option_click(this.id)">Saab</option>
   </optgroup>

DEMO .

Proper way (Working in all browsers)

<select onchange="option_click(this.value)">
    <optgroup label="Swedish Cars">
        <option value="volvo" id="volvo">Volvo</option>
        <option value="saab" id="saab">Saab</option>
    </optgroup>
</select>

DEMO .

An example with switch statement here .