从字符串中提取子字符串

Question

I have the following String:

mac1: 00:11:22:33:44:55
mac2: 66:77:88:99:00:11
model: PI-504
first_name: any_name
device_type: baseboard
serial_number: 668778542298745210

And I want to extract all values into an array. How to do it with Java?

public String[] getvaluesIntoStringArray(String str) {
    ....
}

Answer 1

You can use regular expressions :

private static final Pattern PATTERN = Pattern.compile(".*?:(.*)");

public static String[] getvaluesIntoStringArray(String str) {
    Matcher matcher = PATTERN.matcher(str);
    List<String> values = new ArrayList<String>();
    while (matcher.find())
        values.add(matcher.group(1).trim());
    return values.toArray(new String[values.size()]);
}

Answer 2

If you want to split new lines then I think this should do it

public String[] getvaluesIntoStringArray(String str) {
    return str.split("\\r?\\n");
}

Answer 3

use this regex (?<=:\\s)(.+$) if your regex engine does not suppirt lookbehind use this regex (:\\s)(.+$) matches will be in group 2

ps: use regex with regexoption MultyLine

Answer 4

String str = "mac1: 00:11:22:33:44:55
mac2: 66:77:88:99:00:11
model: PI-504
first_name: any_name
device_type: baseboard
serial_number: 668778542298745210";

String[] tempArr = str.split("\n");

this tempArr should contain the values as mac1: 00:11:22:33:44:55 , mac2: 66:77:88:99:00:11,model: PI-504,first_name: any_name,device_type: baseboard,serial_number: 668778542298745210

Answer 5

请试试

String[] result = str.split("\n");    

Answer 6

Here code:

public static void main(String[] args) {
        List<String> result = new ArrayList<String>();

        String str = "mac1: 00:11:22:33:44:55\n" +
                     "mac2: 66:77:88:99:00:11\n" +
                     "model: PI-504\n" +
                     "first_name: any_name\n" +
                     "device_type: baseboard\n" +
                     "serial_number: 668778542298745210";

        Pattern pattern = Pattern.compile("^.*?:(.*)$", Pattern.MULTILINE);
        Matcher matcher = pattern.matcher(str);
        boolean find = matcher.find();
        while(find) {
            result.add(matcher.group(1));
            find = matcher.find();
        }
        System.out.print(result);
    }