正则表达式搜索空格后跟一个字符

Question

var str = 'The quick brown fox @ ';
var str = str.split(/\s/);
var str = str.join('_');

The result of this operation is "The_quick_brown_fox_@_", How can I only split if the space is followed by a character and this character is not a "@"?

Answer 1

Use lookahead:

str.split(/\s(?=\w)/);

Yields

["The", "quick", "brown", "fox @ "]

Joins into: "The_quick_brown_fox @ "

Answer 2

var str = str.split(/\s(?!@)/);

Answer 3

试试这个正则表达式

/\s[^@A-Za-z]/

Answer 4

use this regex (?!@)(?=[^$])

space

(?!@) next symbol not @

(?=[^$]) ignoring last lone spase

Answer 5

you can use like this without using Regex

var str = 'The quick brown fox @ ';
var n=str.replace(/ /g,"_");