是玩！ Framework 2.0适合创建REST API吗？

Question

I have developed a REST API using Play! Framework 1.2.4, and I have a strong liking for the framework. The simplicity and the rapid development cycle helped me achieve this in a fraction of the time I would have taken had I gone the traditional Java EE route.

Now that I am exploring using Play! 2.0.3 for my next project. I see that while the framework has been enhanced and makes it even easier to develop web-apps , the same cannot be said about REST API's . My app will not have any HTML whatsoever - I will just respond with XML or JSON or whatever data exchange format I decide to use in future.

So, the question is:

Has anyone here used Play 2.0.x for exposing non-html pure REST API's?

More Details:

Here are some of the factors I feel make it more difficult to develop pure REST API's in Play 2.0.x compared to 1.2.x. Please correct my understanding if I am wrong.

Content Negotiation is harder

In play! 1.2.4, I content negotiation was build in to the framework. There were options to define right in the routes file what content-type a request expects.

GET /friends User.listFriends(format:'xml')

Then, in the controller,

public static void getFriends(){
    render();
}

This would result in the views/xml/User/listFriends.xml template being rendered automatically. To add support for JSON tomorrow, all I needed to do was to add a views/json/User/listFriends.json template.

I do not see how this can be done in play! 2.0.x

Creating non-html templates is less intuitive

After some trial and error, I figured out that one can create, for example, a listFriends.scala.xml in the views folder in play! 2.0. Then, it needs to be invoked in the controller code as follows:

return ok(views.xml.listFriends.render()) ;

However, Eclipse doesn't like this, because Eclipse does not know about the views.xml.listFriends since it is generated only after play compilation completes. Is there anything I'm missing here?

Answer 1

In Play (Scala) you can do something like this:

val myXMl = obtainXML();
return Ok(myXML).as("text/xml")

I'm not sure of the syntax in Java, but it would be equivalent: instead of creating a template, you generate the XML and then you send it to the user, setting the return type to "text/xml" (or json or whatever you need it to be).

Answer 2

As Pere Villega explained, but with the Java syntax:

String xml = getXMLAsString();
return ok(xml).as("text/xml");

The as() method is part of the Status class .

Or, an alternative is:

String xml = getXMLAsString();
response().setContentType("text/xml")
return ok(xml);