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使用除dataValueField / dataTextField之外的第三个值将ViewModel绑定到DropDownListFor

[英]Bind a ViewModel to a DropDownListFor with a third value besides dataValueField/dataTextField

When I show a list of testplanViewModels in my View and the user selects one the SelectedTestplanId is returned to the Controller post action. 当我在视图中显示testplanViewModels列表并且用户选择一个列表时,SelectedTestplanId将返回到Controller后操作。 What should also be returned is the TemplateId which belongs to the SelectedTestplanId. 还应该返回的是属于SelectedTestplanId的TemplateId。

When the AutoMapper definition is run the Testplan.TestplanId is implicitly copied over to the TestplanViewModel.TestplanId . 运行AutoMapper定义时,将Testplan.TestplanId隐式复制到TestplanViewModel.TestplanId The same could be done by providing a TemplateId on the TestplanViewModel. 通过在TestplanViewModel上提供TemplateId可以完成相同的操作。 When the user selects now a "TestplanViewModel" in the View, how can I attach the TemplateId to the controller action to access it there? 当用户现在在视图中选择一个“ TestplanViewModel”时,如何将TemplateId附加到控制器动作以在其中访问它? The DropDownList does not allow 2 dataValueFields! DropDownList不允许2个dataValueFields!

CreateMap<Testplan, TestplanViewModel>().ForMember(dest => dest.Name, opt => opt.MapFrom(src => string.Format("{0}-{1}-{2}-{3}", src.Release.Name, src.Template.Name, src.CreatedAt, src.CreatedBy)));

public ActionResult OpenTestplanViewModels()
{
    IEnumerable<Testplan> testplans = _testplanDataProvider.GetTestplans();          
    var viewModel = new OpenTestplanViewModel
    {
        DisplayList = Mapper.Map<IEnumerable<Testplan>, IEnumerable<TestplanViewModel>>(testplans)
    };
    return PartialView(viewModel);
}


public class TestplanViewModel
{      
    public int TestplanId { get; set; }     
    public string Name { get; set; }           
}


public class OpenTestplanViewModel
{
    [Required(ErrorMessage = "No item selected.")]
    public int SelectedTestplanId { get; set; } 
    public IEnumerable<TestplanViewModel> DisplayList { get; set; }       
}

OpenTestplanViewModel OpenTestplanViewModel

@using (Html.BeginForm("Open", "Testplan"))
{ 
    @Html.ValidationSummary(false)      
    @Html.DropDownListFor(x => x.SelectedTestplanId, new SelectList(Model.DisplayList, "TestplanId", "Name"), new { @class = "listviewmodel" })  
}

Solution : 解决方案

 public class OpenTestplanViewModel
    {
        [Required(ErrorMessage = "No item selected.")]
        public string TestplanIdAndTemplateId { get; set; } 
        public IEnumerable<TestplanViewModel> DisplayList { get; set; }

        public int SelectedTestplanId
        {
            get
            {
                return Convert.ToInt32(TestplanIdAndTemplateId.Split(new[] { '_' }).First());
            }
        }
        public int SelectedTemplateId
        {
            get
            {
                return Convert.ToInt32(TestplanIdAndTemplateId.Split(new[] { '_' }).Last());
            }
        }   
    }

 CreateMap<Testplan, TestplanViewModel>()
                .ForMember(d => d.Name, o => o.MapFrom(src =>  string.Format("{0}-{1}-{2}-{3}", src.Release.Name, src.Template.Name, src.CreatedAt, src.CreatedBy)))
                .ForMember(d => d.TestplanIdAndTemplateId, o => o.MapFrom(src => src.TestplanId + "_" + src.TemplateId));

HTML doesn't really work that way. HTML并不是真的那样工作。 If you want more than one value returned from the post for the dropdown (the helper generates a select element), you'll have to create a property on your view model that you then parse within the controller. 如果您希望从帖子中为下拉列表返回多个值(帮助程序会生成一个select元素),则必须在视图模型上创建一个属性,然后在控制器中进行解析。

For instance, if you had two integer ID fields, the combined property could create a value that looks something like 23_42 . 例如,如果您有两个整数ID字段,则Combined属性可以创建一个看起来像23_42的值。 You could then use the Split method to get the correct values ( 23 & 42 ) back. 然后,您可以使用Split方法来取回正确的值( 2342 )。

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