迷宫与路径查找算法

Question

I am working on learning how to us a A* algorithm to find paths and I want to see the best way of doing this. This is what I was thinking I want to have a start point and end point then build the maze via a build function then populate it with obstetrical then runt the A* algorithm the print off the route in a table like format basically changing the 0 to a 3 to show the path that is taken (obstetrical will equal a 1). Does this sound like a good plan?

What I am having trouble with is that I don't know the best way to put in the obstetrical in the array. This is what I have so far:

public class Maze {

/**
 * @param args the command line arguments
 */
public static void main(String[] args) {


    //start and end points in the array
    int startx = 115;
    int starty = 655;
    int endx = 380;
    int endy = 560;
    //number of collums and rows
    int row = 700;
    int col = 500;
    //size of maze
    int maze [][] = new int [row][col];

    makeMaze(row, col, maze);
    printMaze(row, col, maze);



}

 //fill mazz with 0
    private static void makeMaze(int row, int col,  int maze[][])
    {   
         //fill maze with 0 for initilization
        for(int i = 0; i < row; i++)
        {
            for(int j = 0; j < col; j++)
            {
                maze[i][j] = 0;
            }

        }
    }
    //print out array/maze
    private static void printMaze(int row, int col,  int maze[][])
    {
         //... Print array in rectangular form
        for(int i = 0; i < row; i++)
        {
            for(int j = 0; j < col; j++)
            {
                System.out.print(" " + maze[i][j] );
            }
            System.out.println("");
        }

    }
    //fill the array with obsticals
    private void makeObsticals()
    {
        //obstical 1
        //this represent the corners of the object
        int ob1Point1 [][] = new int [220][616];
        int ob1Point2 [][] = new int [220][666];
        int ob1Point3 [][] = new int [251][670];
        int ob1Point4 [][] = new int [272][647];

        //object 2
        int ob2Point1 [][] = new int [341][655];
        int ob2Point2 [][] = new int [359][667];
        int ob2Point3 [][] = new int [374][651];
        int ob2Point4 [][] = new int [366][577];

        //obejct 3
        int ob3Point1 [][] = new int [311][530];
        int ob3Point2 [][] = new int [311][559];
        int ob3Point3 [][] = new int [339][578];
        int ob3Point4 [][] = new int [361][560];
        int ob3Point5 [][] = new int [361][528];
        int ob3Point6 [][] = new int [113][516];

         //object 4
        int ob4Point1 [][] = new int [105][628];
        int ob4Point2 [][] = new int [151][670];
        int ob4Point3 [][] = new int [180][629];
        int ob4Point4 [][] = new int [156][577];
        int ob4Point5 [][] = new int [113][587];

        //object 5
        int ob5Point1 [][] = new int [118][517];
        int ob5Point2 [][] = new int [245][517];
        int ob5Point3 [][] = new int [245][577];
        int ob5Point4 [][] = new int [118][577];

        //object 6
        int ob6Point1 [][] = new int [280][583];
        int ob6Point2 [][] = new int [333][583];
        int ob6Point3 [][] = new int [333][665];
        int ob6Point4 [][] = new int [280][665];

          //object 7
        int ob7Point1 [][] = new int [252][594];
        int ob7Point2 [][] = new int [290][562];
        int ob7Point3 [][] = new int [264][538];

          //object 8
        int ob8Point1 [][] = new int [198][635];
        int ob8Point2 [][] = new int [217][574];
        int ob8Point3 [][] = new int [182][574];


    }
    //astar algorithum
    private void findPath()
    {
    }

}

thanks for any help with this

Answer 1

Sorry but I don't understand why you have declared so many two dimensional array for obstacles... as you said. . .

//obstacle1
//this represent the corners of the object
   int ob1Point1 [][] = new int [220][616];
   int ob1Point2 [][] = new int [220][666];
   int ob1Point3 [][] = new int [251][670];
   int ob1Point4 [][] = new int [272][647];

I think from above code you want to mean (220,616),(220,666),(251,670),(272,647) are corner points of 1 obstacle.

If so then I will suggest not to take 4 two dimensional array but instead mark area covered by obstacle in maze[][] array by infinity ie the highest integer no. (let consider it as a 10000)

and for other (x,y) position,in maze[x][y] put heuristic value of each position (which means cost to reach destination(endx,endy) from that (x,y)position)

and then apply A* algorithm to reach from start to end.