[英]Entity Framework Query Check
Kindly use the following script to Create the tables. 请使用以下脚本创建表。 I am using Entity Framework 3.5
, when i create an edmx
file i do not see the ParentID
column in Nodes
table...why?? 我正在使用Entity Framework 3.5
,当我创建edmx
文件时,在Nodes
表ParentID
不到ParentID
列...为什么? Because of which i cannot execute this query Dim categories = From c In context.Nodes Where (c.ParentID = "1")
i get an error ParentID is not a member of HagglerModel.Nodes
因此,我无法执行此查询Dim categories = From c In context.Nodes Where (c.ParentID = "1")
我收到错误ParentID is not a member of HagglerModel.Nodes
if exists(select name from sysobjects where name = 'NodeInsert' and type = 'tr')
drop trigger NodeInsert
go
if exists(select name from sysobjects where name = 'NodeUpdate' and type = 'tr')
drop trigger NodeUpdate
go
if exists(select name from sysobjects where type = 'u' and name = 'Tree')
Drop table Tree
go
if exists(select name from sysobjects where type = 'u' and name = 'Node')
Drop table Node
go
create table Node(
NodeId int not null,
ParentId int null,
NodeName varchar(255) not null,
constraint PK_Node primary key(NodeId),
constraint UK_NodeName unique(NodeName)
)
go
create table Tree(
NodeId int not null,
ParentId int not null,
Level int not null,
constraint PK_Tree primary key(NodeId, ParentId),
constraint UK_Level unique(NodeId, Level)
)
go
alter table Node
add constraint FK_NodeNode foreign key(ParentId) references Node(NodeId) --on delete cascade
go
alter table Tree
add constraint FK_NodeTreeNode foreign key(NodeId) references Node(NodeId) on delete cascade
go
--alter table Tree
-- add constraint FK_NodeTreeParent foreign key(ParentId) references Node(NodeId) on delete cascade
--go
create trigger NodeInsert on Node for insert as
begin
set nocount on
insert into Tree(NodeId, ParentId, Level)
select NodeId, NodeId, 0
from inserted
insert into Tree(NodeId, ParentId, Level)
select n.NodeId, t.ParentId, t.Level + 1
from inserted n, Tree t
where n.ParentId = t.NodeId
end
go
create trigger NodeUpdate on Node for update as
if update(ParentId)
begin
set nocount on
declare @child table(NodeId int, Level int)
insert into @child(NodeId, Level)
select t.NodeId, t.Level
from inserted n, Tree t
where n.NodeId = t.ParentId and t.Level > 0
delete Tree
where
Tree.NodeId in(select NodeId from @child)
and Tree.ParentId in(
select t.ParentId
from inserted n, Tree t
where n.NodeId = t.NodeId and t.Level > 0
)
delete Tree
where Tree.NodeId in(select NodeId from inserted) and Tree.Level > 0
insert into Tree(NodeId, ParentId, Level)
select n.NodeId, t.ParentId, t.Level + 1
from inserted n, Tree t
where n.ParentId = t.NodeId
insert into Tree(NodeId, ParentId, Level)
select c.NodeId, t.ParentId, t.Level + c.Level
from inserted n, Tree t, @child c
where n.NodeId = t.NodeId and t.Level > 0
end
go
insert into Node(NodeId, ParentId, NodeName) values(1, null, 'A')
insert into Node(NodeId, ParentId, NodeName) values(2, 1, 'B')
insert into Node(NodeId, ParentId, NodeName) values(3, 1, 'C')
insert into Node(NodeId, ParentId, NodeName) values(4, 2, 'D')
insert into Node(NodeId, ParentId, NodeName) values(5, 4, 'E')
insert into Node(NodeId, ParentId, NodeName) values(6, 4, 'F')
insert into Node(NodeId, ParentId, NodeName) values(7, 6, 'G')
select * from Node
select * from Tree
--gets all descendants of the Node 2
select c.*
from Node n, Tree t, Node c
where n.NodeName='B'
and n.NodeId = t.ParentId
and t.NodeId = c.NodeId
--gets path to the root from node 7
select p.*
from Node n, Tree t, Node p
where n.NodeName='G'
and n.NodeId = t.NodeId
and t.ParentId = p.NodeId
--changes parent of node 4 from 2 to 1
update Node set ParentId = 1 where NodeId = 4
select * from Node
select * from Tree
In your case, I guess ParentId, could be an foreign Key. 在您的情况下,我想ParentId可能是外键。 You cannot access foreign key directly. 您不能直接访问外键。
here is an post, on how to achieve it.. Entity Framework: Setting a Foreign Key Property 这是有关如何实现它的文章。 实体框架:设置外键属性
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