如何在Symfony2中将视图文件呈现为json对象以进行Ajax请求

Question

I have an action for login process. Now I want to use the same action for normal login process and for ajax requests also.

        /**
         * @Route("/sponsor/login", name="sponsor_login", options={"expose"=true})
         * @Template("SponsorBundle::login.html.twig")
         * @return array
         */
         public function loginAction()
         {}

I want this action to render different view files for xmlhttp request and for normal http request.How do i do that? and I want to pass view file in a json object

Answer 1

You can do this:

return $this->getRequest()->isXmlHttpRequest()
 ? $this->render(.... "form.html.twig" ....)
 : $this->render(... full page that will include the form ...) ;

or

if ($this->getRequest()->isXmlHttpRequest()){
  $template = "form.html.twig" ;
  $params = ....
} else {
  $template = "login.html.twig" ;
  $params = ....
}

return $this->render($template, $params) ;