PHP基于查询数组添加前导零

Question

I am trying to add leading zeros to all skus in my table. I need every sku to have a 3 digit number in front of it. For 1-9 skus would be 001$row['sku'], 002$row['sku'], 009$row['sku'], 010$row['sku'], 011$row['sku'],...etc I am using $n=sizeof($row). But every time I echo this out I get 22 skus (which there are about 50) and only returns the first letter of the sku. I don't understand how to fix this, I am trying to build an array from my query to determine how many skus there are in order to add leading zeros. Any help is much appreciated.

$result = mysql_query("SELECT * FROM temp_table WHERE po='ABCD'");

$row = mysql_fetch_array($result);

    for ($i=0, $n=sizeof($row); $i<$n; $i++) {
               if ($i < 9) {
                 $Zeros="00";
               }
               elseif ($i < 99) { 
                 $Zeros="0";
                }
               else{
                 $Zeros="";
                }
               $num=$i+1;    
echo   $Zeros.$num. "=" . $row[$i]['sku'] . "`<br />`";

Answer 1

You aren't looping through the resulting data set quite right, or I don't fully understand the situation.

Assuming you want to build a three-digit SKU based on each row's SKU, here's a better way:

// query the database
$result = mysql_query("SELECT * FROM temp_table WHERE po='ABCD'");

$count = 0;

// Loop through every row in the data result set
while ( $row = mysql_fetch_assoc( $result ) ){ 
    $count++; // Increment SKU #

    // Build integer SKU based on count of item in order and pad with zeros
    $this_sku = str_pad( $count, 3, '0', STR_PAD_LEFT);

    // Build onto integer SKU based on row data and pad with zeros
    $this_sku .= str_pad( $row['sku'], 3, '0', STR_PAD_LEFT);

    echo "This product SKU is $this_sku<br/>";
}

Answer 2

I don't fully understand the context, but it sounds as though you want to be using the str_pad function.

eg

$num1 = str_pad(1, 3, '0', STR_PAD_LEFT); // = 001
$num2 = str_pad(10, 3, '0', STR_PAD_LEFT); // = 010
// etc...

Answer 3

You are looking for the str_pad function .

example:

$num = str_pad($input, 4, "0", STR_PAD_LEFT);

Answer 4

最优雅的方法是使用sprintf（） http://php.net/manual/en/function.sprintf.php

sprintf(%'0'3d=%d`<br />`, $num, $row[$i]['sku']);