在javascript中创建一个Json对象

Question

I am in process to validate a form where i need to show certain radio buttons and user need to select them based on some rules,how many number of radio buttons can be created is dynamic so i can not do validation on server side not can write a predefined java-script code for that.

each of the radio buttons will be divided in to groups say required and than further down they can be grouped like center , left , right etc, so from each group user need to select one value, so the structure comes out like this

-Main Group (if block needs to validate based on this e.g if key=required should validate)
  |
  Sub-group (say left, right etc)
   |
   number of radio buttons based on the sub-group

So the main group key can be used to decide if validation should be done on that or not and based on the sub-group key i can decide what all values will be there and needs to be validate

i was planning to create a JSON object on page rendering time like

{"required": [
        {"center": "id1,id2,id3"},
        {"left": "id1,id2,id3"}
      ]
  "optional": [
        {"center": "id1,id2,id3"},
        {"left": "id1,id2,id3"}
      ]
};

i am not sure if the structure i am thinking is right and how to create it in java script? like i have a external loop for key and than one more loop for the sub-group and finally for the buttons in the sub-group,

 for(main group key){
     for(subgroup key){
       for(list of radio button under subgroup key)
}
  }

but not sure how to create a right structure so that i can parse it later with jquery and use that for validation.

Any help in this will really be appreciated.

Answer 1

In javascript. You can use JSON.stringify(myObject, replacer);

For example.

create on javascript object like this

var myObject={};

now after creating javascript object you can convert it into JSON structure like this

var myJsonText=JSON.stringify(myObject);

NOTE: replacer is optional

Now if you want to convert it in JSON Object Use JSON.parse method

myJsonObject=JSON.parse(myJsonText)