Java-当我尝试获取源代码服务器时返回的HTTP响应代码：400

Question

My issue is in my title,also I will give java code and detail.

void getSourceCode(String text_url){

    String source_code="";
    BufferedReader reader = null;

    try {
          reader = new BufferedReader(new InputStreamReader((new URL(text_url)).openStream(), Charset.forName("UTF-8")));
          String inputLine;
          while ((inputLine = reader.readLine()) != null) {
            source_code+=inputLine.replace(" ", "");
          }
    } 

    catch (Exception e) {
        e.printStackTrace();
    } 

    finally {
          if (reader != null) {
                try {
                  reader.close();
                } 
                catch (IOException e) {
                  e.printStackTrace();
                }
          }
    }

    System.out.println( source_code );
}

For example,I send "http://ekenlermangalkomuru.com/urunlerimiz/liste/144/BinarKömürü" as the parameter via html a href="..." parsing but the error report is :

java.io.IOException: Server returned HTTP response code: 400 for URL: http://ekenlermangalkomuru.com/urunlerimiz/liste/144/BinarKömürü
at sun.net.www.protocol.http.HttpURLConnection.getInputStream(Unknown Source) at java.net.URL.openStream(Unknown Source)

The link works on all browsers but when I tried to connect via java code it doesnt work.How I can I solve ? Thanks for all advices..

Answer 1

Error 400 means that the request is malformed so that the server is unable to process it. Are you sure that you have properly URL encoded the request URL? For something like: http://ekenlermangalkomuru.com/urunlerimiz/liste/144 /BinarKömürü, at least ö and ü are not ASCII letters and need to be encoded to create a well-formed request.

Answer 2

Error 400 means that you didn't make a "good" request to the site. I think you would need something more than just a BufferedReader to open a URL via HTTP. That's because the protocol needs to know what you want to see and if you have a cache available etc. To open a URL you should use HttpUrlConnection, check How to send HTTP request in java? out for info, also http://docs.oracle.com/javase/7/docs/api/java/net/HttpURLConnection.html could be of help.