如何在RestEasy中从单个单例公开多个接口

Question

Let's say we have the following service interfaces:

@Path("servicea")
public interface ServiceA {
    @GET void aMethod();
}

@Path("serviceb")
public interface ServiceB {
    @GET void anotherMethod();
}

Now, using RestEasy these can easily be exposed as a Rest service using any of the configuration supported. In this case, we have an implementation for ServiceA and one for ServiceB , which we export via org.jboss.resteasy.spi.Registry , like so:

Registry registry = (Registry) servletContext.getAttribute("org.jboss.resteasy.spi.Registry");
registry.addSingletonResource(serviceAimpl);
registry.addSingletonResource(serviceBimpl);

This works fine. But now, let's say it makes sense to group the two implementation together, under a single class:

public class ServiceImpl implements ServiceA, ServiceB {
    ...
}

Registry registry = (Registry) servletContext.getAttribute("org.jboss.resteasy.spi.Registry");
registry.addSingletonResource(serviceImpl);

I would expect that when I register an object of this class to RestEasy to expose both paths, but it seems like it expose only one of the two. Is there a way to achieve this? Or is this a bug in RestEasy?

Answer 1

Logically the Impl class cannot have two @Path annotation at class level and within a class there can be only one GET method without the @Path . So it is not possible. You can annotate your interface methods with @Path and that would be honoured.