[英]How to compose libraries with Gnu make?
I'm trying to create a library, called Aa, that provides a class A, which depends on the classes B and C, all in their respective files ( .cpp
and .hpp
). 我正在尝试创建一个名为Aa的库,该库在它们各自的文件( .cpp
和.hpp
)中提供了一个类A,该类取决于类B和C。 I usually compiled all my code manually, but as the number of files increased, I wanted to use a makefile. 我通常会手动编译所有代码,但是随着文件数量的增加,我想使用makefile。 Basically, what I would do was: 基本上,我要做的是:
g++ -c A.cpp
g++ -c B.cpp
g++ -c C.cpp
ar rvs A.a *.o
How can I construct a makefile that does this? 如何构造一个可以做到这一点的makefile? Can makefiles even call ar
? makefile甚至可以调用ar
吗?
This is what I tried: 这是我尝试的:
CC=g++
CFLAGS=-c -Wall
objects=C.o B.o
all : A.o $(objects) #Creates the library called A.a.
:ar rvs A.a A.o $(objects)
A.o : $(objects) A.hpp A.cpp
:$(CC) $(CFLAGS) A.cpp
B.o : B.hpp B.cpp
:$(CC) $(CFLAGS) B.cpp
C.o : C.hpp C.cpp
:$(CC) $(CFLAGS) C.cpp
But it seems that my ar rvs Aa Ao $(objects)
instruction isn't even executing. 但是,似乎我的ar rvs Aa Ao $(objects)
指令甚至没有执行。 This makefile produces all the correct .o
files, but doesn't archive them. 此makefile会生成所有正确的.o
文件,但不会将它们存档。
You could use rules and patterns to make it more generic: 您可以使用规则和模式使其更通用:
SRC_DIR = .
CPPFLAGS += -g
INCLUDES = -I.
# variant 1
SRCS ?= $(shell find $(SRC_DIR) -name '*.cpp' | sed "s/[^\/]*\/[^\/]*\///")
# variant 2
SRCS = A.cpp B.cpp
%.o : $(SRC_DIR)/%.cpp
$(CXX) -o $@ $(INCLUDES) $(CPPFLAGS) -c $^
all : A.a
A.a : $(SRCS:.cpp=.o)
$(AR) rsv $@ $^
OK, so my syntax was correct after all, or, at least, a big portion of it was. 好的,所以我的语法毕竟是正确的,或者至少是很大一部分。 I went with a wrong premise that :
's could replace tabs, which is, apparently, not correct after all. 我错了一个前提:
可以替换制表符,这显然是不正确的。
So, this is the code that does what I want: 因此,这是执行我想要的代码:
CC=g++
CFLAGS=-c -Wall
objects=B.o C.o
all : A.a
A.o : $(objects) A.hpp A.cpp
$(CC) $(CFLAGS) A.cpp
B.o : B.hpp B.cpp
$(CC) $(CFLAGS) B.cpp
C.o : C.hpp C.cpp
$(CC) $(CFLAGS) C.cpp
A.a : A.o $(objects)
ar rvs A.a A.o $(objects)
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