在Java中将String转换为int并获取NumberFormatException，无法弄清原因

Question

ipString is a String representation of an IP address with spaces instead of dots.

String[] ipArray = ipString.split(" ");
String ip = "";
for (String part : ipArray){
    if (part != null){
        ip += part;
    }
}
ip = ip.trim();
int ipInt = Integer.parseInt(ip); // Exception is thrown here.

Exception in thread "main" java.lang.NumberFormatException: For input string: " 6622015176 ". Could someone explain why this exception is being thrown?

Answer 1

int is primitive data type and it's range is : -2,147,483,648 to 2,147,483,647

6,622,015,176 is out of int range.

Answer 2

public class test {
    public static void main(String args[]) {
        String ipString="662 20 15 176";
        String[] ipArray = ipString.split(" ");
        String ip = "";
        for (String part : ipArray){
            if (part != null){
                ip += part;
            }
        }
        ip = ip.trim();        
        Long ipInt = Long.parseLong(ip);
        System.out.println(""+ipInt);
    }
}

Answer 3

6,622,015,176这个数字超出整数范围。您应该使用long而不是int，这会为您提供较大的范围。