无法使用sax解析器解析标签

Question

Following is my xml: 以下是我的xml：

 <Body>
  <tag1 xmlns=""> <innerTag></innerTag> </tag1>
  </Body>

The problem is that I am not able to get the string inside <tag1></tag1> , that is <innerTag></innerTag> . 问题是我无法在<tag1></tag1>获取字符串，即<innerTag></innerTag> 。 Following is my logic: 以下是我的逻辑：

public void startElement(final String uri, final String localName,
            final String qName, final Attributes attributes)
            throws SAXException {
        if ("tag1".equalsIgnoreCase(qName)){
            inTag1 = true;
            System.out.println("start");
        }
}


public void endElement(final String uri, final String localName,
            final String qName) throws SAXException {
        if ("tag1".equalsIgnoreCase(qName)) {
            System.out.println("end");
            inTag1 = false;
        }
}

public void characters(final char[] ch, final int start, final int length) {

        if (inTag1) {
            System.out.println("@@@" + new String(ch, start, length));
        }
    }
}

But it is giving me empty output. 但这给了我空的输出。 Can anyone help. 谁能帮忙。

Answer 1

In your comment to UVM's answer you wrote 在您对UVM答案的评论中，您写了

Actually inner tag is a kind of xml inside this xml. 实际上，内部标记是该xml中的一种xml。 So I want that as a whole 所以我希望整体上

There is no way to tell the SAX parser to not process all of the XML inside an element and return the entire contents as a string. 没有办法告诉SAX解析器不要处理元素中的所有XML并以字符串形式返回整个内容。 Essentially, you have two options: 本质上，您有两个选择：

reconstruct the XML string, by listening out to all of the SAX events and building the XML string up yourself, or 通过侦听所有SAX事件并自己构建XML字符串来重建XML字符串，或者
if you're in control of the XML documents you're attempting to parse, changing the format of them to something like 如果您要控制XML文档，请尝试将其格式更改为类似
```
 <Body> <tag1 xmlns=""><![CDATA[ <innerTag></innerTag> ]]></tag1> </Body> 
```

Answer 2

You need to check "innerTag" intead of "tag1" 您需要检查"tag1" "innerTag"

if ("innerTag".equalsIgnoreCase(qName)){
            inTag1 = true;
            System.out.println("start");
        }

Basically your innerTag is a child element of tag1.So SAX parser keep on parsing because for it, it is till a valid XML element. 基本上，您的innerTag是tag1的子元素。因此，SAX解析器会继续对其进行解析，因为对于它而言，直到有效的XML元素为止。

无法使用sax解析器解析标签

问题描述

2 个解决方案

解决方案1
1 已采纳 2012-09-23 10:21:56

解决方案2
0 2012-09-23 10:06:27

无法使用sax解析器解析标签

问题描述

2 个解决方案

解决方案1 1 已采纳 2012-09-23 10:21:56

解决方案2 0 2012-09-23 10:06:27

解决方案1
1 已采纳 2012-09-23 10:21:56

解决方案2
0 2012-09-23 10:06:27