取决于if语句的不同数组值

Question

I am building a web crawler which scans links, titles and meta descriptions from links that are found from one url submitted

This if statement i think is correct. $description is the variable which holds all the descriptions from the array $link. But i notice not all sites have a meta description (wikipedia for example) so i have decided that i would like the first twenty characters to act as the description if the description is empty. (By the way, the function and calling of everything works, i just wanted you to see it)

     if ($description == '') {
    $html = file_get_contents($link);    
    preg_match('%(<p[^>]*>.*?</p>)%i', $html, $re);
    $res = get_custom_excerpt($re[1]);
    echo "\n";
    echo $res;
    echo "\n";

    }

However, in the array, the links are stored in [link], the title of the link in [title] and the description in [description]. But i don't know how i would cope with adding $res to my array and to only use if the if statement works.

$output = Array();

   foreach ($links as $thisLink) {
   $output[] = array("link" => $thisLink, "title" => Titles($thisLink), "description" => getMetas($thisLink), getMetas($res));
     } 
    print_r($output);

Answer 1

You can use array_push() to add $res back to your array and then evaluate the array however you need to; not 100% sure what you're trying to do...

Answer 2

From your wording I think you want to do this:

$outputs = array();

foreach ($links as $thisLink) {
    $output = array("link" => $thisLink, "title" => Titles($thisLink), "description" => getMetas($thisLink));

    if ($output['description'] == null) {
        $output['description'] = getMetas($res);
    }

    $outputs[] = $output;
}

You might want to adjust the if statement because I do not know what getMetas() returns when there is not description.